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sin is a function. this is what you do always:
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Mathematics: Post your doubts here!
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here's a joke
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Hai.I cant get it.I m not sure.The question u just gave me here is it a past year?What year it is?yea exactlyy..! that's what i was writing
seee if u can solve this equation :
View attachment 39455
and make it into
View attachment 39456
Here it is...yea exactlyy..! that's what i was writing
seee if u can solve this equation :
View attachment 39455
and make it into
View attachment 39456
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Shouldn't it be h= fg^(-1) since we're changing the position of g(x)?
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I'm re-posting this,. anyone??http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_31.pdf
I need some help with qn no. 8(i and ii). Could anyone please help me understand the solutions?
Thanks
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Actually it would be done this way. I was also confused about it
f (x) = hg(x)
(x-2)^2 + 3
Now, since hg is a composite function, the value of g, which is x-2, would have to be put into the value of h in such a way that it becomes, (x-2)^2 + 3.
Thus h would be x^2 + 3. You can put in the value of g now and you will get f(x)
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I don't get it...how is (x-2)^2 + 3 relevant?
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f = (x-2) ^2 + 3, and that is what the composite function hg(x) is equal to and as g = x-2, we have to make hg(x) equal to f(x)
h(g)= g^2 +3 = (x-2)^2 + 3 thus our answer is x^2+3
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thankkss a lot man!! that was wat i was asking !!
here u go periyasamy
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Thank u a lot.Sorry for the early trouble.thankkss a lot man!! that was wat i was asking !!
here u go periyasamy
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no trouble at all
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nope its not this way
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I guess, we have to take h=f inverse g, isn't it ?
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I still don't get it
the f inverse is root of(x-3) + 2
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Where is the question
? I'll try to solve it.10 The function f is defined by f : x → 2x
2 − 12x + 13 for 0 ≤ x ≤ A, where A is a constant.
(i) Express f(x) in the form a(x + b)
2 + c, where a, b and c are constants. [3]
(ii) State the value of A for which the graph of y = f(x) has a line of symmetry. [1]
(iii) When A has this value, find the range of f. [2]
The function g is defined by g : x → 2x
2 − 12x + 13 for x ≥ 4.
(iv) Explain why g has an inverse. [1]
(v) Obtain an expression, in terms of x, for g−1
(x). [3]
2 − 12x + 13 for 0 ≤ x ≤ A, where A is a constant.
(i) Express f(x) in the form a(x + b)
2 + c, where a, b and c are constants. [3]
(ii) State the value of A for which the graph of y = f(x) has a line of symmetry. [1]
(iii) When A has this value, find the range of f. [2]
The function g is defined by g : x → 2x
2 − 12x + 13 for x ≥ 4.
(iv) Explain why g has an inverse. [1]
(v) Obtain an expression, in terms of x, for g−1
(x). [3]