Mathematics: Post your doubts here!

[ZaqZainab]

Thought blocker this might make more sense

 

[Suchal Riaz]

you told me to do f inverse

anyways thanks for your time and to usama i got it

that was supposed to give the correct answer. i don't know why it doesn't. maybe i need to check it. but i am not in mood.
and did you get it by my explanation or someone else explained it to you?

 

[usama321]

that was supposed to give the correct answer. i don't know why it doesn't. maybe i need to check it. but i am not in mood.
and did you get it by my explanation or someone else explained it to you?

Well Suchal, there are things called a bit complicated questions Not every question is easy. I had done this one before by using inverse, and did not get the right answer. I don't know the reason why it gives the wrong answer though

 

[Thought blocker]

Suchal Riaz do q10ii) from http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_s09_qp_1.pdf

 

[ZaqZainab]

that was supposed to give the correct answer. i don't know why it doesn't. maybe i need to check it. but i am not in mood.
and did you get it by my explanation or someone else explained it to you?

usama explained and thought blocker you were kinda late but i appreciate you helped
i was just trying to say its not simple even you thought it was f inverse the same happened with me

 

[Thought blocker]

usama explained and thought blocker you were kinda late but i appreciate you helped
i was just trying to say its not simple even you thought it was f inverse the same happened with me

SAME HAPPENED TO ME! :'(

 

[Thought blocker]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s09_qp_1.pdf
question 10

10
i) 2(x^2-6x)+13
=2(x-3)^2+13
2(x^2-6x+9)+13
2x^2-12x+18 (-18+13=-5)
so 2(x-3)^2-5 ; a=2 b=-3 c=-5

ii) At x = 3 there is line of symmetry so A = x value so 1 is given zero and from 2(x-3)^2-5 we get A as 3 but we have 2 out the bracket hence A=6

iii) Range means all the values of y axes that graph covers, here , it is from xero to 13

iv) We have to show that it is one to one function so at x= 3 it is one to one, and 4 > 3 it has an inverse

v) Replace x by y and y by x
2(y-3)^2-5=x
make y the subject
we get y = ((root of x + 5)/2) + 3
replace y with f inverse sign and here is your answer.

Good luck

 

[daredevil]

plz solve this quest and explain too

 

[Suchal Riaz]

usama explained and thought blocker you were kinda late but i appreciate you helped
i was just trying to say its not simple even you thought it was f inverse the same happened with me

actually i didn't to the complete question. when i looked at f(x) in completed-sqaure form it suddenly struck to me how it has to be done. and believe me i have done this question. maybe in mocks. but as i didn't do complete question and i had to go for dinner at that time, i told you wrong answer.

 

[Suchal Riaz]

asma tareen ZaqZainab usama321 Thought blocker
please tell me which papers to do of math M1 and P1 before 2009
I want most tricky papers. not just-another-paper.

 

[Thought blocker]

asma tareen ZaqZainab usama321 Thought blocker
please tell me which papers to do of math M1 and P1 before 2009
I want most tricky papers. not just-another-paper.

I told you on fb!!! How was that ?

 

[ZaqZainab]

asma tareen ZaqZainab usama321 Thought blocker
please tell me which papers to do of math M1 and P1 before 2009
I want most tricky papers. not just-another-paper.

i found the papers quite easy before 2009

 

[Suchal Riaz]

i found the papers quite easy before 2009

i have done after 2010. and i will do 2013 on the last day.

 

[Suchal Riaz]

I told you on fb!!! How was that ?

i want before 2009
and i did those questions wrong because i wasn't in mood of doing anything.
after question 3 my all questions are correct. and it was not a difficult paper.
a good paper is one from which you can learn something. where the examiner can trick you, even for a moment.
but P1 is all like find max point, find point of intersection find area under graph etc
i have been doing these kinds of questions for two years

 

[Thought blocker]

i have done after 2010. and i will do 2013 on the last day.

did u upload that 2011 paper on dropbox ?

 

[Suchal Riaz]

believe me add math is harder than P1 and M1
and i have an A* in that.
i want hard questions to solve. i don't want to waste time in doing simple questions.

 

[Thought blocker]

i want before 2009
and i did those questions wrong because i wasn't in mood of doing anything.
after question 3 my all questions are correct. and it was not a difficult paper.
a good paper is one from which you can learn something. where the examiner can trick you, even for a moment.
but P1 is all like find max point, find point of intersection find area under graph etc
i have been doing these kinds of questions for two years

Upload that solutions bro!

 

[Suchal Riaz]

did u upload that 2011 paper on dropbox ?

no. and i won't. its not neat. i did it in parts. in different locations.

 

[Thought blocker]

no. and i won't. its not neat. i did it in parts. in different locations.

:'(

 

[sumeru]

View attachment 39587

plz solve this quest and explain too

Since the line lies in the plane, the product of direction of line and the plane's normal must be zero.....so, you'll get one equation from this...and similarly, the points (4,2,-1) lies in the plane...so they must satisfy the equation of the plane....put these values in x,y,z you will get another equation.....solve them and you will get the respective values...