Oct nov 13 varient 32 question 3 and 4 :/ Aly Emran View attachment 39374
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Oct nov 13 varient 32 question 3 and 4 :/ Aly Emran View attachment 39374
Can you solve part iii ,Hi ,this is the way.Ok .
from part 1 u get=>>-tant
given point is(acos^3t,asin^3t)----->These r the coordinates
y-y1=m(x-x1)
y-asin^3t=-tant(x-acos^3t)
U continue expanding it n u will get it....
yes this gives us only one value and the ms says twqo values :/Do u mean this que 2(3^x-1)=3^x
If that is the one,expand the mod n u will get 2(3^x)-2(1)=3^x
then 2(3^x)-1(3^x)=2
(3^x)=2
then u can get the x.
I hope it helps.
Can you solve part ii & iii , i cant get it even with expanding
whats the other valueyes this gives us only one value and the ms says twqo values :/
whats the other value
sumeru,Bro thanks for the solution today man.But i dont get a slight part in it.I underlined it here.Do u mind to explain it to me man.It can't be integration by parts.So whats it?Thanks man.Sorry man,very dumb in maths.
what is Sin^3(t) + Cos^3(t)?
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