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Thanks..It depends on what type of uncertainty you're working with.
There's the random uncertainty in which you use a range of readings. This is:
(Maximum value - Minimum value) / Number of readings
The random uncertainty is the absolute uncertainty. It's the +- value you see after the main value.
Eg. 28 +- 0.02 seconds, 0.02 seconds is the absolute/random uncertainty
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Then there's the uncertainty involved with taking readings from instruments, like a voltmeter/scale/stopwatch etc. These are different for each instrument, but basically, the precision of each instrument is the absolute uncertainty.
Voltmeter precision = 0.01 V
If you have a voltmeter with voltage 5.67 V.
Your final value will be 5.67 +- 0.01 V
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Next there's percentage uncertainty,
Absolute uncertainty ( this is the precision of the instrument you're using in the exam ) / Your reading * 100
So if your reading is 15 V. The precision of the voltmeter is 0.01
Your percentage uncertainty is [ 0.01/15 ]*100
Bur recently I did one practical, and in it we had to time the oscillation for 10 swings. The stopwatch provided had precision of o.o1 s. So I took the uncertainity by 0.01/my value*100. But the mark scheme said the uncertainity should be between 0.2s to 0.5s .
The question paper was WINTER 2014 paper 36, Question 2 diii. Do check and please reply.