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Haha happens sometimesOh my lord!
idk wat the hell I hve been reading xP
Thankyew....I got it finally xD
And you're welcome
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Haha happens sometimesOh my lord!
idk wat the hell I hve been reading xP
Thankyew....I got it finally xD
Use Hess's Law and construct a cycleCan anyone explain this to me? Thank You.!
E. Change of formation of CO2= -395kjmol^-1
E. Change of formation of H2O= -297kimol^-1
E. Change of combustion of C2H6= -1620kJmol^-1
Calculate the enthalpy of the formation of ethane.
[-2(395)+3(-297)]-(-1620)
= -61kJmol^-1
WHY?
Can anyone explain this to me? Thank You.!
E. Change of formation of CO2= -395kjmol^-1
E. Change of formation of H2O= -297kimol^-1
E. Change of combustion of C2H6= -1620kJmol^-1
Calculate the enthalpy of the formation of ethane.
[-2(395)+3(-297)]-(-1620)
= -61kJmol^-1
WHY?
Reaction is ES so will require Cl2+AlCl3/FeCl3Asak ppl
can someone tell me in Q4 (d) for reaction 2, is heating necessary ?
http://onlineexamhelp.com/wp-content/uploads/2014/08/9701_s14_qp_42.pdf
yea thats wat my miss taught me but ms says heat :/Reaction is ES so will require Cl2+AlCl3/FeCl3
Well,isnt KMnO4 an oxidising agent?IT IS first and foremost,its the conditions that cause it to break the C=C,but along with that it will oxidise anything it can ,which include the OH and COH groups.HNE is a reactive compound.
CH3(CH2) 4CH(OH)CH=CHCHO
(c) Give the structural formulae of all of the carbon-containing compounds formed in each case when HNE is reacted separately with the following reagents.
(i) hot concentrated manganate(VII) ions in acid solution.
So what I came up with is: CH3(CH2)4CH(OH)CO2H + HO2CHO
but in the markscheme the OH- group and the CHO group have also been oxidised giving: CH3(CH2)4COCO2H and HO2CCO2H
What i don't get is that it says manganate ions, not dichromate, so how can the alcohol and the aldehyde group get oxidised as well?
Are you sure its Hot Conc K2Cr2O7 and not KMnO4?Q what will be the result of oxidising this compound with Hot conc K2cR2O7.
Acc to me there should be no change!! any help will be appreciated!
CH4(g) + 2O2(g) -------> CO2(g) + 2H2O(l)A mixture of 10cm3 of methane and 10cm3 of ethane was sparked with an excess of oxygen. After cooling to room temperature, the residual gas was passed through aqueous potassium hydroxide. All gas volumes were measured at the same temperature and pressure. What volume of gas was absorbed by the alkali?
A 15 cm3
B 20 cm3
C 30 cm3
D 40 cm3
the answer is C. i keep getting 36 cm3. now i know that their reaction would produce carbon dioxide and water. then the gases remaining would be excess O2 and CO2 at room temp and pressure. i think only CO2 would be absorbed by the alkali right? I'm not getting 30, could someone help me please?
Eqn 1 : Sn2+ = Sn4+ + 2e-A solution of Sn2+ ions will reduce an acidified solution of MnO4 – ions to Mn2+ ions. The Sn2+ ions are oxidised to Sn4+ ions in this reaction. How many moles of Mn2+ ions are formed when a solution containing 9.5 g of SnCl 2 (Mr: 190) is added to an excess of acidified KMnO4 solution?
A 0.010
B 0.020
C 0.050
D 0.125
the answer is B. i dont get how?
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