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CH4(g) + 2O2(g) -------> CO2(g) + 2H2O(l)
C2H6(g) + 3.5O2(g) --------> 2CO2(g) + 3H2O(l)
Residual gas is CO2 which is absorbed by KOH(aq)
CO2(g) + OH-(aq) ---------> CO3(-2)(aq) + H2O(l)
Volume of CO2 produced by CH4 and C2H6 is 10 and 20 cm^3 respectively, total volume of CO2 produced = 30 cm^3
thank you so very much!!Eqn 1 : Sn2+ = Sn4+ + 2e-
Eqn 2 : MnO4- + 8H+ + 5e- = Mn2+ + 4H2O
These equations are available in data booklet : http://www.cie.org.uk/images/164870-2016-specimen-data-booklet.pdf
Balance the number of electrons, SHOULD BE EQUAL IN BOTH THE EQN.
Eqn 1 : 5Sn2+ = 5Sn4+ + 10e-
Eqn 2 : 2MnO4- + 16H+ + 10e- = 2Mn2+ + 8H2O
Add Eqn 1 with Eqn 2 = 5Sn2+ + 2MnO4- + 16H+ = 5Sn4+ + 2Mn2+ + 8H2O
Ignore liquids, we are just taking ions into account.
2moles of MnO4- reacts with 5moles of Sn2+
2 Mn---> 5 Sn
0.4 Mn <- 1 Sn
Hence, 9.5/190 * 0.4 = 0.02mol