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Chemistry: Post your doubts here!

The Sarcastic Retard

The Sarcastic Retard

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donewithtime80 said:
Can u please explain your working? It's going over my head :p
Click to expand...
I used trial and error.
I tried option A, didnt satisfied the answer, but B did. Sth like this;
Initial moles of 2P : 2
IM of 2Q and R : 0
Equilibrium moles of R : x
EM of 2Q is x/2 (1:2 ratio)
EM of 2P is 2 - x/2 (1:2 ratio and IM was 2 so we will subtrct x/2)
So addition of EM = 2 - x/2 + x/2 + x = 2 + x
 
D

donewithtime80

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The Sarcastic Retard said:
I used trial and error.
I tried option A, didnt satisfied the answer, but B did. Sth like this;
Initial moles of 2P : 2
IM of 2Q and R : 0
Equilibrium moles of R : x
EM of 2Q is x/2 (1:2 ratio)
EM of 2P is 2 - x/2 (1:2 ratio and IM was 2 so we will subtrct x/2)
So addition of EM = 2 - x/2 + x/2 + x = 2 + x
Click to expand...
kayy!! thanks bro!
 
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