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Chemistry: Post your doubts here!

P

Paruna

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12
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donewithtime80 said:
View attachment 57498

why isn't it B and Y D?
Click to expand...

In the question, you are only given the molecular formula of the compound which is C4H8. Yes, it's an alkene, but the structural formula is unknown.
During the hydrogenation of C4H8, it produces methylpropane. Therefore, before reaction of hydrogen, the alkene should have been 2-methylprop-1-ene.
Now, that you know the structural formula of the alkene, you can easily proceed with the question! =)
That's how I proceeded with the question- I do have a doubt for the last bit though :/20151104_171935.jpg
 
krishnapatelzz

krishnapatelzz

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252
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donewithtime80 said:
In a car engine, non-metallic element X forms a pollutant oxide Y. Further oxidation of Y to Z occurs spontaneously in the atmosphere. In this further oxidation, 1mol of Y reacts with 0.5mol of gaseous oxygen.

is it oxides of carbon or nitrogen?
Click to expand...
which oxide are you talking about Y or Z
 
S

Sinzzzz

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9
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heyy!
can someone explain this please
Alkane X has molecular formula C4H10. X reacts with Cl 2(g) in the presence of sunlight to produce only two different monochloroalkanes, C4H9Cl. Both of these monochloroalkanes produce the same alkene Y, and no other organic products, when they are treated with hot ethanolic KOH. What is produced when Y is treated with hot concentrated acidified KMnO4?
A CO2 and CH3CH2CO2H
B CO2 and CH3COCH3
C HCO2H and CH3COCH3
D CH3CO2H only
The answer is B, why not A?
 
The Sarcastic Retard

The Sarcastic Retard

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donewithtime80 said:
26 Use of the Data Booklet is relevant to this question.
2.30 g of ethanol were mixed with aqueous acidified potassium dichromate(VI).
The desired product was collected by immediate distillation under gentle warming. The yield of product was 70.0%.
What mass of product was collected?

A 1.54g
B 1.61g
C 2.10g
D 3.14g
Click to expand...
Mr of ethanol = 46
Mr of ethanoicacid = 60
n of ethanol = 0.05mol
1 : 1 ratio
mass of ethanoicacid = 0.05 * 60 * 70% = C
 
A

awesomaholic101

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2,266
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Sinzzzz said:
heyy!
can someone explain this please
Alkane X has molecular formula C4H10. X reacts with Cl 2(g) in the presence of sunlight to produce only two different monochloroalkanes, C4H9Cl. Both of these monochloroalkanes produce the same alkene Y, and no other organic products, when they are treated with hot ethanolic KOH. What is produced when Y is treated with hot concentrated acidified KMnO4?
A CO2 and CH3CH2CO2H
B CO2 and CH3COCH3
C HCO2H and CH3COCH3
D CH3CO2H only
The answer is B, why not A?
Click to expand...
The chloroalkenes formed will have 2 methyl branches, only then alkenes formed by both isomers will be same.
 
The Sarcastic Retard

The Sarcastic Retard

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Sinzzzz said:
heyy!
can someone explain this please
Alkane X has molecular formula C4H10. X reacts with Cl 2(g) in the presence of sunlight to produce only two different monochloroalkanes, C4H9Cl. Both of these monochloroalkanes produce the same alkene Y, and no other organic products, when they are treated with hot ethanolic KOH. What is produced when Y is treated with hot concentrated acidified KMnO4?
A CO2 and CH3CH2CO2H
B CO2 and CH3COCH3
C HCO2H and CH3COCH3
D CH3CO2H only
The answer is B, why not A?
Click to expand...
THere are two posiblities of forming alkenes in primary Halogenoalkane.
There is only one posiblity of forming alkene in tertiary.
Hence:
WIN_20151104_20_05_02_Pro.jpg
 
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