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how did you end up with x^2 +3Actually it would be done this way. I was also confused about it
f (x) = hg(x)
(x-2)^2 + 3
Now, since hg is a composite function, the value of g, which is x-2, would have to be put into the value of h in such a way that it becomes, (x-2)^2 + 3.
Thus h would be x^2 + 3. You can put in the value of g now and you will get f(x)