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Hey guys...Can anybody explain me q10 of s12 paper 12?
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D?,,help
how?..plx explain..
Since it is transverse wave, the speed same throughout and displacement varies.The option C about K.E is purely rubbish. While the option D is correct because it is a fact.how?..plx explain..
I had solve this question, go few pages back or gimme paper linkhewlp
Actually the particle is changing its direction. Thus, from moving downwards to moving upwards, there is a change in direction. I am not sure about the speed here, but the acceleration would be high due to the change in direction, as acceleration has both magnitude and directionSince it is transverse wave, the speed same throughout and displacement varies.The option C about K.E is purely rubbish. While the option D is correct because it is a fact.
29)http://papers.xtremepapers.com/CIE/...nd AS Level/Physics (9702)/9702_s12_qp_12.pdf
questions 29,34,36,37,38,39 please!
9)
http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_s07_qp_1.pdfI had solve this question, go few pages back or gimme paper link
V1= 5000/ (5000+5000) x 2 = 1V then V2= 3000/ (3000 + 2000) x 2 = 1.2 so V1 - V2 = -0.2 so C
i'm sooo sooo sorry i pasted the wrong link x_x i it was supposed to be w12 not s12 ugh!29)
c = f * λ
We know f = 1 / t
so c = 1 / t * λ
t = λ / c
now it took 3 wavefronts to reach XY to P
so t = 3λ / c
34)
View attachment 44703
36)
Its obviously D :
As Light intensity increases, its resistace decreases, so as R = V / I , R α V, so As R decreases, V would also decrease across LDR.
37)
current is passing through both lamps so they will glow dimly. dimly because the current will be less as now there are two compared to one light bulbs.
38)
What's hard in this ?
Find resistance in each case
3 would be highest with 0.7Ω
and 1 would be least with 0.4Ω
39)
Theory part maat pucho, chapter parho and then na aye to phucho
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