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Physics: Post your doubts here!

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Apparatus :
Loudspeaker (switched on)
Glass tube with an open end
Detector

Method :

1) Place the loudspeaker infront of the open end of the glass tube
2) Move the detector along the glass tube and measure the distance between two CONSECUTIVE regions which show zero/min intensity on the detector
3) Take set of values and average them to eliminate random error
4) Finally, equate the distance measured with 1/2(lambda)

so lambda (wavelength) = 2d (unit specified)
 
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Can you please help with Q6 c ii) of the same paper
Untitled.png
Here if you can not understand my writings there :p
Distance b/w two nodes is lambda/2 ; and length of nodes was 34
hence 34 * 2 = lambda = 68 cm , we take SI units, hence 0.68 m
Now, As f = v / lambda ; 340 / 0.68 = 500 Hz :)
Hope you got it :)

Alternative way :¬

Distance between node and antinode is lambda / 4
hence then length is 17 ; now 17 * 4 = lambda = 68 cm i.e 0.68 m
now same thing f = 340 / 0.68 = 500 Hz

Anyway you can do it :)
 
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Thank you, but i wanted the (i) part and (iv)

Look for Part (i) The Electric field Is The direction where Positive Charge Moves.Physics.JPG

And part (iv) :- It Would Rotate due to Torque Produced. .(Plus forces are oppsite and equal) To Align with the electric field :) .. The rotation would be Clockwise.. Because Positive End would be Towards The direction of Electric field.! :)
 
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Look for Part (i) The Electric field Is The direction where Positive Charge Moves.View attachment 42385

And part (iv) :- It Would Rotate due to Torque Produced. .(Plus forces are oppsite and equal) To Align with the electric field :) .. The rotation would be Clockwise.. Because Positive End would be Towards The direction of Electric field.! :)
ty ib bunch ;)
 
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