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Physics: Post your doubts here!

gary221

gary221

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leosco1995 said:
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s09_qp_4.pdf

Q6 (b) (i) State and explain the polarity of the pole P of the magnet.

How do you figure this out? :s
Click to expand...

Yup..i was confused too..
Bt see, the weight on the balance increases, which means there is a force on the magnet acting DOWNWARDS.
According to Newton's 3rd law (action-reaction law), there is an UPWARD force on the wire..
And so, according to Fleming's left hand rule, P is the north pole.
Hope u gt it!!
:D
 
gary221

gary221

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salvatore said:
Thanks..

And what about part 2, the ratio question?
Click to expand...
On it... :)
okay, so max (light fringe) amp = add the 2 amps (A + B) = 2+1.4 = 3.4 units
min amp(dark fringe) = A - B = 2-1.4 = 0.6 units
n since intensity is proportional to amplitude^2
thus, (3.4)^2 / (0.6)^2 = 32
Hope u gt it!!
 
snowbrood

snowbrood

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gary221 said:
On it... :)
okay, so max (light fringe) amp = add the 2 amps (A + B) = 2+1.4 = 3.4 units
min amp(dark fringe) = A - B = 2-1.4 = 0.6 units
n since intensity is proportional to amplitude^2
thus, (3.4)^2 / (0.6)^2 = 32
Hope u gt it!!
Click to expand...
can u answer q .5 b(ii) from physics coursebook exam style questions page no 118
 
salvatore

salvatore

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gary221 said:
On it... :)
okay, so max (light fringe) amp = add the 2 amps (A + B) = 2+1.4 = 3.4 units
min amp(dark fringe) = A - B = 2-1.4 = 0.6 units
n since intensity is proportional to amplitude^2
thus, (3.4)^2 / (0.6)^2 = 32
Hope u gt it!!
Click to expand...
Oh yeah! Thanks :)
 
salvatore

salvatore

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snowbrood said:
can u answer q .5 b(ii) from physics coursebook exam style questions page no 118
Click to expand...
I just interfered! :p
For b(i) 800 × 0.5 × 9.81 = ρX × 0.6 × 9.81 [1]
ρX = 666 ≈ 670 kg m−3
= 666 kg/m^3

(iv) ρhg = 666 × 9.81 × 0.7 [1]
pressure = 4580Pa

Your answers are correct!
 
snowbrood

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salvatore said:
I just interfered! :p
For b(i) 800 × 0.5 × 9.81 = ρX × 0.6 × 9.81 [1]
ρX = 666 ≈ 670 kg m−3
= 666 kg/m^3

(iv) ρhg = 666 × 9.81 × 0.7 [1]
pressure = 4580Pa

Your answers are correct!
Click to expand...
u just helped thanks man i just wanted answers thanks anyways
 
VelaneDeBeaute

VelaneDeBeaute

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A*(a*) said:
Can you please help me with this? https://www.xtremepapers.com/community/attachments/23499/
Click to expand...

Velocity is the gradient of the acceleration-time graph. Following that, the graph C seems the viable option. If you look closely, toh the gradient of a-t graph increases from a horizontal slope, decreases and reaches back a 0 gradient at its maximum point. That is what the graph C shows! :)
Concentrate a little and you'll surely understand! :)
 
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