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Physics: Post your doubts here!

ahmed abdulla

ahmed abdulla

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any help with phase difference ...? second time posting about this ....plz help
when they say another wave has phase fifference 90 .. how to draw it ..... and how to find phase difference betwween two points
 
VelaneDeBeaute

VelaneDeBeaute

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ahmed abdulla said:
any help with phase difference ...? second time posting about this ....plz help
when they say another wave has phase fifference 90 .. how to draw it ..... and how to find phase difference betwween two points
Click to expand...

You shift the same wave 90 degrees ahead! :)
 
Minato112

Minato112

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A*(a*) said:
can someone help me pleasssseeee?View attachment 23499
Click to expand...
Answer B. Acceleration is given by the gradient of a velocity-time graph. You have to look at the gradients of the 4 graphs and you will notice that the graph in B corresponds to it. Let's analyse it. Split the graph (in A) into 3 parts. First you notice that the gradient increases implying that acceleration increases. Then the gradient becomes zero ===> that acceleration is now on a horizontal point. Finally, when the velocity decreases, the gradient decreases and thus the acceleration decreases.

Note : I did this in a real hurry. Please check the answer mayB I didn't read the question correctly.
 
A*(a*)

A*(a*)

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Minato112 said:
Answer B. Acceleration is given by the gradient of a velocity-time graph. You have to look at the gradients of the 4 graphs and you will notice that the graph in B corresponds to it. Let's analyse it. Split the graph (in A) into 3 parts. First you notice that the gradient increases implying that acceleration increases. Then the gradient becomes zero ===> that acceleration is now on a horizontal point. Finally, when the velocity decreases, the gradient decreases and thus the acceleration decreases.

Note : I did this in a real hurry. Please check the answer mayB I didn't read the question correctly.
Click to expand...

Yes thats exactly what I thought but the answer to our misfortune is A! B looks so possible.
 
littlecloud11

littlecloud11

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Untitled.png

Initial velocity is 8.4, so your starting point is (0, 8.4). The time taken for the ball to reach the ground is .47 second and the velocity with which it reaches the ground is 12.9, so your second point is (.47, 12.9). The velocity increased and the ball accelerated so it's a straight line with an increasing gradient. The ball remained in contact with the ground for .02 s so there was a time lapse within which the velocity changed, this is shown by the dotted line. The velocity fell from 12.9 to -4.2 as the direction is now reversed and the ball begins to move up.so your next point is (.49, -4.2)
the rebound velocity is 4.2. Use v = u+ at to calculate the time after which the ball comes to rest. 0 = 4.2 + 10* t, t= .42 sec
total time the ball traveled =.47 + .02+ .42 = .91 sec and it's final velocity is 0 m/s
so your final point is (.91, 0)

salvatore
 
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