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Maths, Addmaths and Statistics: Post your doubts here!

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Re: O'level Maths, Addmaths and Statistics help available he

scouserlfc said:
oh well ill tell u that thing because i think i got over that problem but if i have ill be back !
anyways,
can u solve this question !
http://xtremepapers.net/CIE/Cambridge%2 ... 4_qp_2.pdf
Q11/b)iv and v) !

thanks !
OX = 1/3 (2p + q)
QY = p + q(k - 1)

(b) (iv) OX is parallel to QY, so the coefficients of p and q must be in a fixed ratio. The coefficients of p are 2/3 and 1 whereas those of q are 1/3 and (k - 1). Therefore,
2/3 divided by 1 = 1/3 divided by (k-1)
=> 2/3 = 1/3(k-1)
=> 2(K-1) = 1
=> k = 1/2 + 1 = 1.5.

(v) OZYQ would form a parallelogram since the two pairs of sides are parallel to their opposite sides.
OZ = QY (equal vectors because they are opposite sides of a parallelogram)
OZ = p + 1/2 q
PZ = OZ - OP
=> PZ = p + 1/2 q - p
So, PZ = 1/2 q.

:)
 
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Re: O'level Maths, Addmaths and Statistics help available he

^^ Well i guess they meant that both are parallel !
 
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Re: O'level Maths, Addmaths and Statistics help available he

scouserlfc said:
But in the MS why have they written this !

Lambda(OX)=QY im talking abt part iv) remember that !
.
heres the link ! http://xtremepapers.net/CIE/Cambridge%2 ... s04_ms.pdf :unknown: .

BTW thanks for the help :Bravo: :good:
Yes, you may include that in your answer as well. Same ratio method as I used. Lamda OX = QY merely means that the ratios of the coefficients would be constant.
You're welcome. :D
 
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Re: O'level Maths, Addmaths and Statistics help available he

okay now i want to know how difficult a topic is LOCI ! and has it come int he recent year in the PP and in what paper does it come !
thank you !
 
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Re: O'level Maths, Addmaths and Statistics help available he

LOCI is related to construction work, and it is easy if you get the 4 to 5 concepts that are involved with it. Just practice and you'll be good with it. It comes in the paper1 with a question ranging from 3 to 7 marks.
 
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Re: O'level Maths, Addmaths and Statistics help available he

check out stats paper 4 nov06 paper2 sec2 Q9(ii)(b) n (c).....what i dnt get hre is dat...d no of d 1st person selected is 75.so what wil b d no.s of d rest of d people selected?05,15,25,35,45,55,65,85, or wil v select every 9th person 4m dat row?plz reply asap
 
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Re: O'level Maths, Addmaths and Statistics help available he

The number of the first person selected can't be 75 because it doesn't lies in the range 00-09 that you gave in part (a). Hence, the first resident selected will be 01 beacause it is the first number from the range that can be found in the second row. For part (c), you just select every 10th following number from the number you selected. So after 01 you'll select 11th then 21st and so on, this is what you call systematics sampling.

Hope this helped! :)
 
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Re: O'level Maths, Addmaths and Statistics help available he

another q....in stats paper1 nov07 d er says dat d answer 2 q1(iii) is 4.6.hws dat possible?
 
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Re: O'level Maths, Addmaths and Statistics help available he

aleezay said:
another q....in stats paper1 nov07 d er says dat d answer 2 q1(iii) is 4.6.hws dat possible?
I believe the answer is correct.
Formula
(A1/A2)=(r1/r2)^2
(50.3*25/58.8 )=r^2
r^2=21.3860
r=4.6
 
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Re: O'level Maths, Addmaths and Statistics help available he

CaptainDanger said:
Add bracket to the expression to make it correct

3+48÷4 into 6 - 1 = 4

Its quite simple I know... But I am just unable to do it.... :'( Give me hint for such type of question too...

MINATO I'l try to help

it's quite simple use this B.O.D.M.S.A (Bracket Of Division Multiplication Substraction Addition)
 
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Re: O'level Maths, Addmaths and Statistics help available he

3 + 48 / (4 x 6) - 1 = 4
Try fitting the brackets around different numbers and see how it works out.
It's BODMAS, by the way. Addition comes before subtraction. :)
 
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stats help needed
nov07P2Q2(ii)
nov08P1Q7(i)b & Q10(iii)
nov08P2Q7(v) & Q8b
nov09P2Q3(ii)

plz reply asap
 
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Re: O'level Maths, Addmaths and Statistics help available he

Actually I posted the answer for these but as the site was going through updating so I think my post wasn't successfully published. Anyways I will again upload the solution :)
 
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