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The equation was:HI. Can someone help me with this please?
QP: http://onlineexamhelp.com/wp-content/uploads/2013/11/9709_w12_qp_31.pdf
9709/31/ON/12 Q7 (ii). When I equate the denominator to 0, shouldn't I get both x=0 and 3y^3-1=0 ? Why does the mark scheme solve for only 3y^3-1=0?
MS: http://onlineexamhelp.com/wp-content/uploads/2013/11/9709_w12_ms_31.pdf
Thank you!
ln(xy) − y^3 = 1
Any logarthmmic function, ln(x), is only defined for the domain (0,infinity), this equation cannot be evaluated at x=0.
Domain is 0<x<inf.
btw I've been told that log functions are defined for negative numbers in more advanced mathematics, so this may be technically wrong but I think for A2 this is what you're supposed to know. (Cuz I never took A2)