• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Mathematics: Post your doubts here!

S

sessionmay2013

Messages
6
Reaction score
25
Points
3
Hey fellas, if any of you could help me a little with this super simple question, it would be much appreciated! (y)
When it comes to partial fractions in paper 3, I know how to express a rational fraction as partial fractions when the denominator (bottom part of fraction) is
(ax + b)(cx + d)(ex + f),
OR
(ax + b)(cx + d)²

BUT I wouldn't know how to approach a problem where you have to express a fraction with the denominator
(ax + b)(x²+c²)
as partial fractions.
I'm sure it just a simple step I haven't come across to before, so if anyone could explain this to me it would be GREATLY appreciated! Thanks beforehand! Cheers! :)
 
syed1995

syed1995

Messages
1,824
Reaction score
949
Points
123
sessionmay2013 said:
Hey fellas, if any of you could help me a little with this super simple question, it would be much appreciated! (y)
When it comes to partial fractions in paper 3, I know how to express a rational fraction as partial fractions when the denominator (bottom part of fraction) is
(ax + b)(cx + d)(ex + f),
OR
(ax + b)(cx + d)²

BUT I wouldn't know how to approach a problem where you have to express a fraction with the denominator
(ax + b)(x²+c²)
as partial fractions.
I'm sure it just a simple step I haven't come across to before, so if anyone could explain this to me it would be GREATLY appreciated! Thanks beforehand! Cheers! :)
Click to expand...

the (ax+b)(x^2+c^2) will become (Ax+B)/x^2+c^2 + C/(ax+b) I guess.. I would like you to confirm this from someone else as well before you start using it :) Link me a question and I will be able to help better.. I don't do well in the question with "in terms of"
 
Namehere

Namehere

Messages
264
Reaction score
395
Points
73
Can someone explain how to do Q6 first part?
 

Attachments

  • 9709_w13_qp_32.pdf
    90.1 KB · Views: 12
  • 9709_w13_ms_32.pdf
    490.5 KB · Views: 1
ZaqZainab

ZaqZainab

Messages
1,764
Reaction score
3,472
Points
273
Gehad Mohamed said:
Hello can someone please explain Q 6 (iii)
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s13_qp_62.pdf
Click to expand...
ZaqZainab said:
okay so method one which in my attachment is 3
is when Not all next to each other lets take an example
3 Blue pens and 4 green
Find the possible arrangements when not ALL green next to each other
we can have it like this
|||||||
but if its method 2 which is in my attachment 4
you cant have it like this you are suppose to have it
||||||| or any other way in which a green is not next to another green
BUT sometime both the methods work when you have
for example 3 blue and 2 green
just because the number is 2 that's why
Click to expand...
we have a total of 12 tress lets take tress other than hibiscus
so we have 8 tress
8! diffrenent arrangemnts
coming to the hibiscus tree 4 of them have 9 different places
so
9P4
Multiply them
 
Serenia

Serenia

Messages
21
Reaction score
28
Points
23
Hello!

Can you please please help me in this question of Pure Maths 3?

It is question 5. You can just give a brief outline of the solution. I was able to find the derivative of the function and equate it to zero. I got what is on the mark scheme, but from there I couldn't eliminate y to find an equation for x. I just need someone to tell me how to do it in words, I can do the rest. :)

Thanks. Any help is appreciated.

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s13_qp_32.pdf
http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s13_ms_32.pdf
 
You must log in or register to reply here.
Top