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Mathematics: Post your doubts here!

C

CЯeScɘnt

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syed1995

syed1995

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abruzzi said:
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_33.pdf
Please please pleaseee help me with qn 8(ii)
Click to expand...

There are a lot of ways to solve this..

the easiest will be to do a cross product of both the line's direction vector.. since they lie on the plane.. their perpendicular will be the normal vector of the plane.

the cross product of both direction vectors gives.. (-11,10,7)

that is your plane equation -11i+10j+7k=d

d=r.n take any point on the plane and multiply with normal vector to get the answer. Take the point of intersection you got in part i.
d=(-11,10,7).(7,-1,2)
d=-73

Final equation is

-11i+10j+7k=-73
 
abruzzi

abruzzi

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syed1995 said:
There are a lot of ways to solve this..

the easiest will be to do a cross product of both the line's direction vector.. since they lie on the plane.. their perpendicular will be the normal vector of the plane.

the cross product of both direction vectors gives.. (-11,10,7)

that is your plane equation -11i+10j+7k=d

d=r.n take any point on the plane and multiply with normal vector to get the answer. Take the point of intersection you got in part i.
d=(-11,10,7).(7,-1,2)
d=-73

Final equation is

-11i+10j+7k=-73
Click to expand...
I thought the two lines won't have the same perpendicular since they intersect.
Thanks a lot bro, jazakallah
 
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cheemaboyz

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can anyone help me in this question please i have my exam so please help me
Ques :- The times for a certain car journey have a normal distribution with mean 100 minutes and standard deviation 7 minutes. Journey times are classified as follows: ‘short’ (the shortest 33% of times), ‘long’ (the longest 33% of times), ‘standard’ (the remaining 34% of times).
(i) Find the probability that a randomly chosen car journey takes between 85 and 100 minutes. [3]
(ii) Find the least and greatest times for ‘standard’ journeys. [4]
 
Thought blocker

Thought blocker

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