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yes
4i)
When you solve OP.OQ you get its value as to
and use, |OP|.|OQ|cos theta = OP.OQ
you get is root 14 times root 14 cos theta = 2
so, 14cos thea = 2 ; cos theta = 1/7
ii)
q-p = 4 - 2 + q - 1 = 6
so q = 5
thanks Thought blocker is fli
thanksDarling, sup with chem ?