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Mathematics: Post your doubts here!

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Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!

AOA!
This is what I got. Are these answers correct?
q10. (c) (i) p= 2 and q = 3.
(ii) 4850
(iii) n = 20.
 
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Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!

aoa:
can someone help me with angles on the circle thing
i dont know really stuck on it
plz
any help will be appreciated
 
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Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!

Well they are really easy !! Just remember all the properties and your good to go !! :D

If you don't understand any question please post it here !! i will be happy to help you !! :)
 
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Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!

1bilalm said:
aoa:
can someone help me with angles on the circle thing
i dont know really stuck on it
plz
any help will be appreciated

Maths!

CHECK HERE
 

XPFMember

XPRS Moderator
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Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!

plz post the link to the paper!! i'll try to check it :)
 
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Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!

can someone please help me !! there are questions on past papers that say: find the next two prime numbers after 53 .. how do we work it out???
 
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cupcake76 said:
can someone please help me !! there are questions on past papers that say: find the next two prime numbers after 53 .. how do we work it out???
59,61
 
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Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!

correct, salmanpakrocks! :)
 
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Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!

so u added them up n^2+(n+1)^2 , but they should equal to 2n^2 +2n+1 which is 2n(n+1)+1 so can u tell me how
sry for too much asking
 
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Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!

How come ??
n^2+(n+1)^2 = 2n^2+n = 2n(n+1) simple !!
 
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Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!

Ramosk95 is right there... You got that wrong Salman... You have to use (a+b)^2 formula there.... On (n+1)^2
 
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Re: IGCSE Maths Tips nov.2010!Confused!have questions?Post h

Ramosk95 said:
hello ,,
stuck on question 9 may/june2007 b(ii) z=??? plzz hlp
thanks
http://www.xtremepapers.me/CIE/Cambridg ... 7_qp_4.pdf

Anyway thats not the right way

Hello

z=2n^2+2n


You have to use the formula here of quadratic sequence....

a + (n-1) d1 + 1/2 (n-1) (n-2) d2

a is the first number of sequence,
d1 first difference,
d2 second difference...

So a=4
d1=8
d2=4

Put these and solve you will arrive at 2n^2+2n... Which is the answer...

Still any confusions? Don't hesitate... We are always here to help others... :)
 

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Re: IGCSE Maths Tips nov.2010!Confused!have questions?Post h

Ramosk95 said:
hello ,,
stuck on question 9 may/june2007 b(ii) z=??? plzz hlp
thanks
http://www.xtremepapers.me/CIE/Cambridg ... 7_qp_4.pdf
Hello!! :)

well as i always say...sequences are very easy...u dont need these complicated formulas...atleast for IGCSE's ;)so here try to look it through...link the last row with the ones in the beginning...

i tried and finally i realized there's a link with the first row...the one with the heading Diagram!!

if u notice....divide each with the no. in the first row...

u'll get 4, 6 , 8 , 10

so that means to get
n=1 => 4 x 1
n-2 => 6 x 2
n=3 => 8 x 3
so for n=n how is it going to be??
for the sequence 4, 6, 8, 10...the nth term is 2n + 2...this is the simple AP

so substituting in the pattern above
n=n => (2n + 2) x n
is the expression for the nth term...hope u got that clear!! :)

if u still wud want to learn the formulas it's ur wish ....but be sure nt to mess uo the formula :)
 
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Re: IGCSE Maths Tips nov.2010!Confused!have questions?Post h

Math_angel said:
Ramosk95 said:
hello ,,
stuck on question 9 may/june2007 b(ii) z=??? plzz hlp
thanks
http://www.xtremepapers.me/CIE/Cambridg ... 7_qp_4.pdf
Hello!! :)

well as i always say...sequences are very easy...u dont need these complicated formulas...atleast for IGCSE's ;)so here try to look it through...link the last row with the ones in the beginning...

i tried and finally i realized there's a link with the first row...the one with the heading Diagram!!

if u notice....divide each with the no. in the first row...

u'll get 4, 6 , 8 , 10

Nice !! :)

so that means to get
n=1 => 4 x 1
n-2 => 6 x 2
n=3 => 8 x 3
so for n=n how is it going to be??
for the sequence 4, 6, 8, 10...the nth term is 2n + 2...this is the simple AP

so substituting in the pattern above
n=n => (2n + 2) x n
is the expression for the nth term...hope u got that clear!! :)

if u still wud want to learn the formulas it's ur wish ....but be sure nt to mess uo the formula :)
 
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Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!

CaptainDanger said:
TSZ said:
well Basim Nazir, u do deserve a thnku...u've spent a lot of time doing dis 'nd helped me bt i still hve sum problems relating these topics. first of all, in the oct nov 2006 paper 2, isn't the question 5 abt a tower alongside a boat of length 33m, 'nd u have to find the length of the tower 'nd question 19 part b abt finding the values of x and y using matrix multiplication. Also i asked abt may june 2010 paper 2 variant 1. In may june 2010 paper 4 variant 1 question 2 part b, hw u gt the ans, like 190+3n/40+n, vat is the logic? Q4 part c, hw do u find the matrix because i knw da matrice(rote memorization) bt wat calculation do u show, i asked him, he says no just write the matrix no need for calculation bt i dunt knw if dats right. now Q 5 part c y did u multiply 180 and cos35. Q 9 c, vat values do i put in t he formula? I really appreciate ure help...thnx once again...'nd of course i'll pray 4 ure result 'nd IA u'll get all A*'s and i'll also pray for ure families health.

I can make his work easier if you tell me the paper code??

I don't really like someone making my work easier... 'If everything was made easier; what should I do now?' :) No offence! :) And yes, it's 0580... You asked him the code, indirectly he's making your work easier, if you would have thought, you would have get the code by now! No offence again man! :)
 
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