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How was Mathematics Paper 72 (Statistics 2)?

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Q3
E(X) was 150, Var (X) was 30,000 (I accidentally wrote the s.d. tho :( )
In the last q I'm afraid you had to divide P(X<4) by P(X>=1) :S
I got the same answer for Q3 but for the conditional probability i did what shrz09 said
 
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What do you guys say the GT will be? I say It'll be lower this time..a 40.
My guess is 37, as it had 2 tricky qs and that is the gt papers with tricky qs get
Bear in mind this is xtremepapers so this will be a terrible sample to know the overall GT as obviously users on xtremepapers are more 'keen', if that makes sense.
 
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I also got E(x) 150 and Var(x) 30000, as far as q5 is considered it was regarding confidence intervals,part 3 was (0.96)^4 as per binomial process.While as per my concepts the conditional probability was not p(x<4)/p(x is greater or equal to 1).Rather it was p(x=1,2,3)/p(x is greater or equal to 1) as zero is not an intersection between p(x is greater or equal to 1) and p(x<4)
yep, exactly what I did for both questions
 
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So what do you guys think the OVERALL Grade Threshold will be this year for an A* in maths? Assuming you did P 12 and 62 last year, and 32 and 72 this year
 
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How can you get 30,000 as variance? That makes the mean 150, and standard deviation 173.2 (if variance = 30,000). Do you really think the standard deviation can be greater than the mean? Think again. :)
 
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How can you get 30,000 as variance? That makes the mean 150, and standard deviation 173.2 (if variance = 30,000). Do you really think the standard deviation can be greater than the mean? Think again. :)
Of course it can
Google it
Think again :)
 
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I don't recall getting any standard deviation in S2 that was greater than the mean. But oh well, we'll have to wait till the marking scheme is out to decide that. :)
 
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Yes it is possible, you can get a variance greater than mean, but you can't get a sd greater than the mean
 
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