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I'm not sure it requires a genius.
Sure; in (iv) you should know that the expression in part (iii) is zero (because you got -c-3 for (iii)).
For parts (ii) and (iii) you note that, because the string is slack, the particle is moving under gravity only. So you treat it as a projectile (parabolic motion) and use those equations. So no it's not linear motion (although, as you should know, for projectile motion, you can treat the vertical and the horizontal as two separate linear motions).
I got it now. Thank you so much. It's really a big help.
Show your working, I'll happily correct it.Hello, can anyone post the solution to June 04 Q5 the second part please? I did my calculation, treated it as projectile, resolved the speed and all but couldn't get the answer (so close yet so far). Maybe I miscalculated somewhere. Just wanna check where exactly. Thank you.
I have solved it. Want it?
Excellent explanation. Thanks.
No problem.
Notes on Vector and Vector space can be found here
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