Chemistry: Post your doubts here!

[A*****]

Hold on, the oxidizing agent should be the KMnO4 and not sulfuric acid

Sulfuric acid is used with KMnO4 during oxidation that is why we write 'acidified' KMnO4

 

[A*****]

Do you mean that the answer was B and not D?

No it is D

 

[Kanekii]

The H+ ion in this full equation comes from sulfuric acid.
3CH3CH2OH + Cr2O72- + H+ = CH3CHO + 7H20
but this equation is out of the syllabus or for simplicity it is written as:
CH3CH2OH + [O] = CH3CHO + H20

 

[Metanoia]

Sulfuric acid is used with KMnO4 during oxidation that is why we write 'acidified' KMnO4

yes, it is used to provide an acidic environment, but it is not the oxidizing agent, the KMnO4 is the oxidising agent

 

[Metanoia]

Idk why I am confusing this all but can u plz write an equation to show the behaviour of sulfuric acid as an acid in the reaction with ethanol?

H2So4 + CH3CH2OH --> HSo4- + [CH3CH2OH2]+

It donates a proton (acts as an acid) to ethanol

 

[MShaheerUddin]

HELP

 

[A*****]

View attachment 63754
HELP

It is C

 

[MShaheerUddin]

It is C

H2O is also formed in this reaction right?

 

[A*****]

H2O is also formed in this reaction right?

Yeah

 

[MShaheerUddin]

But, why didn't they mention it? :/

 

[A*****]

But, why didn't they mention it? :/

That's pretty obvious...they said that X is the only CHLORINE CONTAINING COMPOUND, didn't say that it is the only product

 

[MShaheerUddin]

Right

 

[A*****]

Apart from general guessing, can this question be solved arithmetically?

 

[innovative_1]

Apart from general guessing, can this question be solved arithmetically?

B??

 

[A*****]

B??

Yes

 

[innovative_1]

Apart from general guessing, can this question be solved arithmetically?

Look 1 mol is produced by cracking the ethene, methane n propene 0.5 mol of ethene already given in the question so we need to find the ratio of other products mol so like 0.5+0.25+0.25= 1 mole to convert it into whole number we just multiply with 4 so by adding them we will get 8 carbon altogether

 

[A*****]

Look 1 mol is produced by cracking the ethene, methane n propene 0.5 mol of ethene already given in the question so we need to find the ratio of other products mol so like 0.5+0.25+0.25= 1 mole to convert it into whole number we just multiply with 4 so by adding them we will get 8 carbon altogether

Thanx bro!

 

[khadijaimran]

how do you do this please?

 

[Hamnah Zahoor]

how do you do this please?

Ester breakage of the compound will help you identify it.

 

[khadijaimran]

t

View attachment 63764
Ester breakage of the compound will help you identify it.

thankyou so much ))