Chemistry: Post your doubts here!

[Kanekii]

For 32, O has 2 unpaired p electrons and for the Cl+, u need to understand that Cl atom has 5 p electrons, 2 paired and 1 unpaired...when Cl+ is formed, the electron removed is from the full p orbital, leaving 2 unpaired p electrons behind
Once u understand this, u can easily work out 2 and 3

Thank youuu so mucchh

 

[A*****]

Plz help me with these

 

[innovative_1]

Plz help me with these

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Well for 14 ig it is B? As thermal decomposition is always endothermic while in reaction 2 it is exothermic because the it is the formation of the product so energy released

 

[innovative_1]

Plz help me with these

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Well for 33 it is D? I'm not sure tho let take an option 2 which is not possible bcoz it is reversible reaction so it can shift backward so less so4 is formed

 

[innovative_1]

Plz help me with these

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24 it's C?

 

[A*****]

Well for 14 ig it is B? As thermal decomposition is always endothermic while in reaction 2 it is exothermic because the it is the formation of the product so energy released

Yes it is B
I'm a bit confused about reaction 2...there will be some bonds breaking as well which is endothermic so how do we know that the overall reaction is exo?

 

[A*****]

Well for 33 it is D? I'm not sure tho let take an option 2 which is not possible bcoz it is reversible reaction so it can shift backward so less so4 is formed

Oh yes tysm

 

[A*****]

24 it's C?

No it's A
How are the bonds supposed to break in this compound?

 

[innovative_1]

Yes it is B
I'm a bit confused about reaction 2...there will be some bonds breaking as well which is endothermic so how do we know that the overall reaction is exo?

For this type of question we consider overall reaction like see only one product is formed from reaction 2 for reaction one 2 formed means bonds r broken

 

[innovative_1]

No it's A
How are the bonds supposed to break in this compound?

Cracking results in formation of alkanes n alkene like suppose it is long chain of ch3ch2ch2ch2ch=ch2 so if u see W alkene is formed when bond broken between ch2 and ch

 

[A*****]

Cracking results in formation of alkanes n alkene like suppose it is long chain of ch3ch2ch2ch2ch=ch2 so if u see W alkene is formed when bond broken between ch2 and ch

But how will Z form?

 

[Kanekii]

But how will Z form?

The question states which of these combinations can form from cracking so we can make multiple combinations for example:
CH3(CH2)5CH=CH2 = CH3(CH2)2CH3 + CH2=CHCH=CH2
which now proves Z is correct.
CH3(CH2)5CH=CH2 = CH3CH=CH2 + CH2=CH2 + CH2=CHCH3
Similarly X and W is proved.
CH3(CH2)5CH=CH2 = CH3CH2CH3 + CH2=C=CH2 +CH2=CH2
Y proved.
Hope it helps ^^

 

[A*****]

The question states which of these combinations can form from cracking so we can make multiple combinations for example:
CH3(CH2)5CH=CH2 = CH3(CH2)2CH3 + CH2=CHCH=CH2
which now proves Z is correct.
CH3(CH2)5CH=CH2 = CH3CH=CH2 + CH2=CH2 + CH2=CHCH3
Similarly X and W is proved.
CH3(CH2)5CH=CH2 = CH3CH2CH3 + CH2=C=CH2 +CH2=CH2
Y proved.
Hope it helps ^^

So we can make anything out of it, right?

 

[Kanekii]

So we can make anything out of it, right?

Yes since this equation 1 which proved Z was from the examiner report and its impossible to form the given compound by only using W,X,Y and Z but the product must contain atleast one of the following

 

[abbas haider]

The question states which of these combinations can form from cracking so we can make multiple combinations for example:
CH3(CH2)5CH=CH2 = CH3(CH2)2CH3 + CH2=CHCH=CH2
which now proves Z is correct.
CH3(CH2)5CH=CH2 = CH3CH=CH2 + CH2=CH2 + CH2=CHCH3
Similarly X and W is proved.
CH3(CH2)5CH=CH2 = CH3CH2CH3 + CH2=C=CH2 +CH2=CH2
Y proved.
Hope it helps ^^

Actually in cracking reactions you can make any alkane or alkene (given that no of carbon atoms and hydrogen atoms are less or equal to the reactant (Alkane Or Alkene )

Btw I thaught only cracking of alkanes is possible.... anyidea if cracking of Alkynes or Arenes possible or not???

 

[Kanekii]

Need Help with these :3

 

[Metanoia]

No it's A
How are the bonds supposed to break in this compound?

Theoretically, as long as the products have same or lesser carbons than the original molecule, they can be formed upon cracking

 

[Metanoia]

Well for 33 it is D? I'm not sure tho let take an option 2 which is not possible bcoz it is reversible reaction so it can shift backward so less so4 is formed

H2SO4 + aq => H^+ + H2SO4^-
Due to full dissociation at the first stage, from 1 mole of H2SO4, we will get 1 mole of H+ and 1 mole of HSO4^-

HSO4^-(aq) <=> H^+(aq) + SO4^2-
Due to partial dissociation at the second stage, from 1 mole of HSO4^-, we will get << 1 mole of H+ and << 1 mole of SO4^2-

Therefore
[SO4^2- (aq)] is low
[HSO4^-(aq)] >> [SO4^2-(aq)]

 

[Metanoia]

Actually in cracking reactions you can make any alkane or alkene (given that no of carbon atoms and hydrogen atoms are less or equal to the reactant (Alkane Or Alkene )

Btw I thaught only cracking of alkanes is possible.... anyidea if cracking of Alkynes or Arenes possible or not???

Yes, possible to crack with enough energy. But the issue is that they do not yield products of much commercial value in most cases

 

[aisya farooq]

Plz help me with these

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Plz help me with these

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enthalpy change of Hydration is always exothermic. hence reaction 2 is exothermic