Chemistry: Post your doubts here!

[Awesome12]

if it involves onle one Fe3+ then y do we mutiply the conc wid 2....SO42- = weak base ...it doesnt affect the pH...isnt tht so?

I didnt really understand your question but from what i understand:
We multiply it by 2 as the conc of Fe2(SO4)3 is 0.1. The equation is given for just 1 mole, [Fe(H20)6]^+2 is the same as Fe^+3 (aq).
The acid dissociation constant will stay the same as a change in conc. Of the acid will also change the conc of the products. Thus we need not worry about Ka and just use the conc. Of the acid as 0.2

Generally speaking, t does affect the pH but only to a very small extent, that WE can term it negligible, For stronger acid, the change is greater which is why we say there is a change.

Again i didnt quite understand what was your question, so i just typed in what I assumed you were asking

 

[Saad the Paki]

Can anyone tell me from where I can practice questions relating to IR spectrometer?

If you find something please share them here. I'm also not very well prepared regarding IR spectroscopy.

 

[Rizwan Javed]

If you find something please share them here. I'm also not very well prepared regarding IR spectroscopy.

Someone told me that this topic can be practiced from the edexcel past papers. I'll share the questions here soon which I found. But if you like you can see the past papers on your own as well.

 

[The Sarcastic Retard]

Someone told me that this topic can be practiced from the edexcel past papers. I'll share the questions here soon which I found. But if you like you can see the past papers on your own as well.

May this help you, found on net.

 

[Rizwan Javed]

May this help you, found on net.

Thanks

 

[princess Anu]

Help part b iv

 

[techgeek]

Anybody found questions on IR spectroscopy in Edexcel papers?

 

[Rizwan Javed]

Anybody found questions on IR spectroscopy in Edexcel papers?

I'll be adding more..

Answer: C

 

[Rizwan Javed]

Marking Scheme:
Absorption due to OH (stretch)/
Peak due to the OH
ALLOW
Alcohol/hydroxyl group

 

[techgeek]

I'll be adding more..
View attachment 60425
Answer: C

thank you so much, could you explain that a little also please? because I didn't get that much from the book

 

[techgeek]

I also found some but from OCR


and the ms:

 

[techgeek]

And this one from AQA:

ms

 

[techgeek]

Different variants have same kind of questions?
I solved all variant 11s now I came back to 12 ones and they all basically seem the same

 

[TariqBhai]

Different variants have same kind of questions?
I solved all variant 11s now I came back to 12 ones and they all basically seem the same

Solve OCR papers then

 

[techgeek]

Solve OCR papers then

yep seems like that

 

[Rizwan Javed]

yep seems like that

Different variants have same kind of questions?
I solved all variant 11s now I came back to 12 ones and they all basically seem the same

Only two papers in every Oct/Nov session only are same. Otherwise, every other paper is different.

 

[ahmedish]

June 13 P41, 1) c) ii)
mark scheme ays its forward (more product) because E is more than 0 (its positive)
but isnt that always the case ?? Even if both half cells is negative its going to be (-0.12)-(-0.67)= positive??
so why are there more products?

 

[farhan141]

Any advice on how to study whole chemistry in 2 weeks? I have done Maths and Physics with past papers just left with chem. Any advice or links/pdfs/pics/notes would be really helpful.

 

[The Sarcastic Retard]

June 13 P41, 1) c) ii)
mark scheme ays its forward (more product) because E is more than 0 (its positive)
but isnt that always the case ?? Even if both half cells is negative its going to be (-0.12)-(-0.67)= positive??
so why are there more products?

If E cell is positive then the reaction will be proceeding in forward direction. This means more products will be formed.

 

[The Sarcastic Retard]

Any advice on how to study whole chemistry in 2 weeks? I have done Maths and Physics with past papers just left with chem. Any advice or links/pdfs/pics/notes would be really helpful.

It depends! chemguide is one of the best site for chemistry. ^_^
Goodluck.