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Option says carboxyllic acid, not ethanoic acid.http://www.sheir.org/a-level-chemistry-11-june2011.pdf
In q 40, how can X be ethanoic acid? The emperical formula is C4 whereas ethanoic has 2 C only??
watz d ans?but my answer comes wrong if I do it this way
I have the solution for this question with the correct ans but
I don't get why we have to multiply moles of H2 by 2
In aqueous solution, the acid HIO disproportionates according to the following equation where m,
n, p and q are simple whole numbers in their lowest ratios.
mHIO → nI2 + pHIO3 + qH2O
This equation can be balanced using oxidation numbers.
What are the values for n and p?
n p
a) 1 2
b) 2 1
c) 4 1
d) 4 2
the answer is B
I know how to figure out the oxidation numbers, but I need explanation on how to balance such equations using oxidation numbers... help please!!
I can only find 8 Carbons that'll form a ketone on oxidation...which one is the ninth one? :/View attachment 54134
Oxidation state of I in HIO, I2 and HIO3 is +1, 0 and +5 respectively.In aqueous solution, the acid HIO disproportionates according to the following equation where m,
n, p and q are simple whole numbers in their lowest ratios.
mHIO → nI2 + pHIO3 + qH2O
This equation can be balanced using oxidation numbers.
What are the values for n and p?
n p
a) 1 2
b) 2 1
c) 4 1
d) 4 2
the answer is B
I know how to figure out the oxidation numbers, but I need explanation on how to balance such equations using oxidation numbers... help please!!
Question is asking for number of fragment molecules containing the ketone group, not number of ketone groups.
so how to find that?
at the double bondsWhere will the cleaving of the molecule occur?
Questions?help please
at the double bonds
I end up with 6 :sCorrect. Break the molecule and then oxidize the areas you've circled. See how many fragments you get that end up with a ketone group.
I end up with 6 :s
http://www.sheir.org/a-level-chemistry-13-nov2010.pdf
Question 25 why not A??
And in 12 my ans is A?
what are the intermediates for each?
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