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Jazak Allah Khair! I knew all those Cu reacns but now, after u explained, everything seems so Clear!There is no specific transition ions that you need to know about that H2O form ligands with.
The most common ones you'll come across are --->
[Fe(H2O)6]^2+ and this can go on to a ligands exchange/ replacement. If, for example, you add concentrated ammonia solution, you'll get [Fe(H2O)2(NH3)4]^2+ and this happens because this complex is more stable than the first one.
Another common one is copper ions. [Cu(H20)6]^2+ ----> this is when there are Cu^2+ ions in solution. This complex gives a pale blue colour.
If sodium hydroxide is added, a blue ppt is formed of Cu(OH)2(H2O)4 is formed.
On adding conc. ammonia solution, you get [Cu(H2O)2(NH3)4]^2+ and this complex is dark blue.
Let's start with [Cu(H20)6]^2+ again. This is, again, blue. Adding conc. hydrochloric acid gives the complex [CuCl4]^2+ which is yellow solution. Notice that the no. of ligands reduces from 6 to 4 and this is because the chloride ions are bigger in size than the H2O molecules.
Hope this was what you were looking for.
