A2 Physics | Post your doubts here

[smartangel]

guys..plz help with the graph question i posted above. also, weird confusion. is it larmor frequency or lamour frequency. application booklet says lamour but all other books i have say larmor and also the marking scheme says larmor!!

 

[angelicsuccubus]

guys..plz help with the graph question i posted above. also, weird confusion. is it larmor frequency or lamour frequency. application booklet says lamour but all other books i have say larmor and also the marking scheme says larmor!!

larmor frequency.

 

[RGBM211]

Using the first law of thermodynamics, explain why the specific latent heat of vaporization is greater than the specific latent heat of fusion for a particular substance?

cn smone explain

 

[SkyPilotage]

you need more energy to make work against atmosphere when the gas is expanding, plus you need more thermal energy to break intermolecular forces.

 

[Abdulrab]

http://www.xtremepapers.com/papers/...nd AS Level/Physics (9702)/9702_s11_qp_41.pdf please do Q 4 (ii) i dont get the question
http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s09_qp_4.pdf and Q9 part b please give a clear solution for this as i dont get it

thanku please reply fast tomorrow i have a paper

 

[angelgirl:)]

http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s07_ms_4.pdf
Q1bi... (MGm/2R) - (gmM/3R) = GMm/6R
how to get 3R?

 

[angelgirl:)]

Q1bi... (MGm/2R) - (gmM/3R) = GMm/6R
how to get 3R?
http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s07_qp_4.pdf

 

[angelgirl:)]

http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_w07_qp_4.pdf
Q1bii...i dont get the vcorrect answer..after apllying force in cord=weight +centripetal force

 

[ousamah112]

Q1bi... (MGm/2R) - (gmM/3R) = GMm/6R
how to get 3R?
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s07_qp_4.pdf

3R is the total distance between the centre of planet and point. For point one = R+R=2R and for the other 2R+R=3R

 

[angelgirl:)]

3R is the total distance between the centre of planet and point. For point one = R+R=2R and for the other 2R+R=3R

but the total distance (the raduis) b/e the planet and the ponit is 2R...so how come its 3R?

 

[alphabravocharlie]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s09_qp_4.pdf
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s09_ms_4.pdf
Q 11 b[iii]

 

[arlery]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s09_qp_4.pdf
Q 10 b[iii]

There's no 10 b iii only 10 b :S

 

[Utsav.]

Q1bi... (MGm/2R) - (gmM/3R) = GMm/6R
how to get 3R?
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s07_qp_4.pdf

the distance is form the center of the earth not the surface of the earth...so including the center there is 3R

 

[alphabravocharlie]

There's no 10 b iii only 10 b :S

SORRY! Q 11 b iii

 

[Utsav.]

P=1\3 (NM<c^2>)\V
is the derivation of this equation important????????????

 

[angelicsuccubus]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s11_qp_41.pdf please do Q 4 (ii) i dont get the question
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s09_qp_4.pdf and Q9 part b please give a clear solution for this as i dont get it

thanku please reply fast tomorrow i have a paper

For Q9 b) the difference in the uncertainties is 10%-2% =8%

That's an uncertainty of 0.08. So to calculate the activity for when the source is not decaying 0.08, it would be decaying 1-0.08= 0.92.
so the activity= 0.092 decay constant=0.693/half life .. and the rest is just
A
= A0 exp(–ln2 t / T½
)

 

[angelicsuccubus]

P=1\3 (NM<c^2>)\V
is the derivation of this equation important????????????

I don't think so.. but the different versions of this equation are..

 

[krazer36]

Umm I know this might seem like a dumb question but it is really confusing me !!! Can you tell me how we got 1.5 in the formula values of example 1 part b?

Link to the example ... http://www.xtremepapers.com/revision/a-level/physics/gravitation.php

Anyone??

 

[Utsav.]

co

For Q9 b) the difference in the uncertainties is 10%-2% =8%

That's an uncertainty of 0.08. So to calculate the activity for when the source is not decaying 0.08, it would be decaying 1-0.08= 0.92.
so the activity= 0.092 decay constant=0.693/half life .. and the rest is just
A
= A0 exp(–ln2 t / T½
)

could you plz elobarte this mate!!!
espically didnt get the part when u said 1-0.08!!!

 

[Utsav.]

I don't think so.. but the different versions of this equation are..

but in the syllabus it is menioned derive bt not rigorous!!!