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MCQ QUESTIONS PLEASE HELP
Q6,17,20,22,24,25,26,27,28,29,38
With explanations, if you can help me with even one question, ty
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_s09_qp_1.pdf
6:
I'd have picked D.
It's between A and D for me. I'll take D because you're getting rid of the double bond so 120 -> significantly lesser.
In A, and Alcohol will be formed but I'm not sure what the bond angles are. Should be lesser on one of the bonds due to the O lone pairs. Still I'd go for D because of the double bond -> single bond.
Edit: I just figured, it's the central carbon atom bond that we need to see not the O-H bond so A is out. A angles are all 109.5, the ones that matter.
17:
D
A- Happening.
B- NH3 -> NH4
C- (NH4)+ and (SO4)2-
D- You're just left with D. If you're unsure and want to waste more time, SO3 s = +6 final S = (-2+S-8)=0 so S= +6 so no redox.
22-
Free Radical Substitution
D
You're subtituting the H with Cl. Remember the very first reaction? FRSR of Alkane? That's what is happening. Don't let the acid part fool you it's the alkane part that's reacting here.
24-
D
Nucleophilic Substitution so both are nucleophiles
25-
B
A gives you propene
B gives you 2 bromo propane
(Remember, Halogenoalkanes, if theres a reaction that's not under ethanolic condition, it'll form an alcohol)
C gives you propene
D Again gives you propene (dehydration of the alcohol)
26:
Oxidation of a primary alcohol can give you Aldehydes and Carboxylic Acids.
27:
B
Ethanol reacting with Butanoic Acid so Ethyl Butanoate
28:
Will get back to you tomorrow.
29:
D
I can't explain this in words. Just draw it out and see where the double bonds would go. Adjacent Carbons in this case. let me know if you dont get it and I'll draw them.
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