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Chemistry: Post your doubts here!

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Hinafatima Answer is B. 0.1 mole of Propanol uses 9/20 mole of 02. 12dm3 is 0.5 mole, so 0.05 is unused. The 0.45 mole of used O2 gives a certain mole of CO2, which you can convert into dm3 and add the dm3 of 0.05 unused mole of O2.
 
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Does anybody know how to calculate Equilibrium Moles in a Kc question
Pls tell me as soon as you can
its URGENT
 
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Does anybody know how to calculate Equilibrium Moles in a Kc question
Pls tell me as soon as you can
its URGENT
The formula for Kc is Kc = ([H+][anion])/[acid]
I'm not entirely sure what kind of math you're stuck in but if you post the question, I might try to solve it for you.
 
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Assalamu Alaikum Warahmathulahi Wabarakathuhu :D

Can any one please explain me this Question................

25strew.jpg

The Answer is B....
Im pretty sure that the answer wont be Either C or D but i just have a doubt like why wouldn't it be A .. Confused... Please Help!!!!!!!1
Thanks in Advance :D
 
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can someone explain me this question
What is the electronic configuration of an element with a second ionisation energy higher than that of each of its neighbours in the Periodic Table?
A 1s2 2s2 2p6 3s2
B 1s2 2s2 2p6 3s2 3p1
C 1s2 2s2 2p6 3s2 3p2
D 1s2 2s2 2p6 3s2 3p3
 
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Can someone help me with this question please

Calculate the pH of a mixture of 25cm3 of 0.1M Ca(OH)2 and 20cm3 of 0.1M HCl.
I was given the answer 12.82 but I'm not sure if it's the correct one.

Thank you!
 
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Assalamu Alaikum Warahmathulahi Wabarakathuhu :D

Can any one please explain me this Question................

25strew.jpg

The Answer is B....
Im pretty sure that the answer wont be Either C or D but i just have a doubt like why wouldn't it be A .. Confused... Please Help!!!!!!!1
Thanks in Advance :D

Here's why it'll never be either of those answers :)

Solvd.jpg
 
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Hey guys! i have a doubt in 9701_s04_qp_2 question (3)(c)(iii) please help! Thanks in advance
View attachment 50680
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Chemistry (9701)/9701_s04_qp_2.pdf

Ok so if you wrote the equation, you'd see that according to stoichiometry, 2 moles of NH3 is required to react with 1 mole of H2SO4. From this, you can get the no of moles of H2SO4

No of moles of H2SO4 required = 1/2 x 0.05(Found in the earlier part!) = 0.025 moles.

Now just apply to C = n/V

C= n/V

V = n/C

V = 0.025/0.5 x 1000 (I multiplied it by 1000 to convert it into cm^3)
V = 50 cm^3

OK?
 
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Asslamoalikum,
I have some problems with the following questions can someone help me as soon as possible. Thanks in advanceWP_20150220_001.jpg WP_20150220_001.jpg WP_20150220_001.jpg WP_20150220_002.jpg WP_20150220_001.jpg WP_20150220_002.jpg WP_20150220_003.jpg WP_20150220_001.jpg WP_20150220_001.jpg WP_20150220_001.jpg
 

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can someone explain me this question
What is the electronic configuration of an element with a second ionisation energy higher than that of each of its neighbours in the Periodic Table?
A 1s2 2s2 2p6 3s2
B 1s2 2s2 2p6 3s2 3p1
C 1s2 2s2 2p6 3s2 3p2
D 1s2 2s2 2p6 3s2 3p3

OK so the answer is B and the reason is the element must be from group 3
The second electron removed will be from sub-shell s which is nearer to the nucleus than p sub-shell. Hence its ionisation energy is higher than group 4 s and higher than group 2 s because it has a higher atomic number.
 
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can anyone help me with this please?
 

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sulphuric acid is an oxidising agent. it is powerful enough to oxidise HBr to Br2 and HI to I2, but it cant oxidise HF and HCl

H2SO4 +HBr= Br2 +2H2O+SO2
H2SO4+HI=I2+2H2O+SO2
 
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