We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
dono waves k crest our trough ki height mai kb difference aye ga?like konsa factor effect krae ga?one complete cycle is 360 deg. so half a wave will be 180 deg. if you start second wave at half point of the first one, you create a phse difference of 180. a quarter you get 90 deg. a thisrd of the quarter and you get 30 deg phase difference. If you still don't get it ask me and I will explain with figures.
Awesome, thank you so much. ^^
it's just 1/2kx^2=1/2mv^2 and the speed used is twice than the speed found in c(i) so.. 16m/s and k is from the beginning 1250N/m and m is 25g and x you're going to get as 72mm
Uh... no. That not how it will be.q1 doesn't have a part c and for 5b(i) .. you just make it lag behind 1/3 of half the wavelength. .. cause 60degrees is pi/3 so its should look like..
View attachment 11083
sorry, shakey hand on the touchpad
How many significant figures must by answer be?
Also in one question my answer was 4.82 but in markscheme its 4.8 so do they cut marks?
Please reply ASAP!!!!
Keep all the answers you're not sure bout to 3.s.f, they can't penalize you for that.
and dude in another question my answer was 7894 but in markscheme its 7900 although i used exact values in my calculation , what about this?They won't cut marks.
Completely sure.
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s11_qp_23.pdf
Q6 c (iv)
How do we make the sketch?
AoA! angelicsuccubus: I think you sort of misread the question. The answer requires a sketch of the same stationary wave 0.25 T later. There's no change in period. So the correct sketch would simply be a straight horizontal line (on the dotted line). leosco1995: In case you're confused, check this simulation: http://en.wikipedia.org/wiki/File:Standing_wave.gifthe new period is 0.25t where t is the old period.. so that means the new wave would occur four times within the old wave.. yeah? cause frequency=1/time period.. so you just draw a wave with the same amplitude but 4 cycles within one wave cycle on fig 6.2... and that would mean that your wave has a quarter of the period of the old wave.
and dude in another question my answer was 7894 but in markscheme its 7900 although i used exact values in my calculation , what about this?
Oh, I see... good thinking.AoA! angelicsuccubus: I think you sort of misread the question. The answer requires a sketch of the same stationary wave 0.25 T later. There's no change in period. So the correct sketch would simply be a straight horizontal line (on the dotted line). leosco1995: In case you're confused, check this simulation: http://en.wikipedia.org/wiki/File:Standing_wave.gif
At t = 0s, the graph is as shown in the question
At t= 0.25 T, the graph is a straight horizontal line
At t= 0.5 T, the graph is again sinusoidal with the antinode 'crest' now being the 'trough' while the nodes remain exactly the same.
At t = 0.75 T, the graph is again a straight horizontal line
At t = T, the same graph as the question again.
(This only applies to a stationary wave. A progressive wave sketch is never horizontal at any time.)
Check this question , the value I obtained was 264900 which I rounded to 265k fr 3 SF but their answer is 2.7x10^5 which is 2 SF . Is it cuz the heigh is in 2 SF?
View attachment 11102
That Is sir a tough question B part!!!hi guys.. can u help me with this?
View attachment 11060
For almost 10 years, the site XtremePapers has been trying very hard to serve its users.
However, we are now struggling to cover its operational costs due to unforeseen circumstances. If we helped you in any way, kindly contribute and be the part of this effort. No act of kindness, no matter how small, is ever wasted.
Click here to Donate Now