- Messages
- 224
- Reaction score
- 183
- Points
- 53
Is current Vector or Scalar ?
Scalar.
We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
Is current Vector or Scalar ?
yeah ih does when they specifically ask for 3 S.F and u lose one mark ,but normally its best to give your answers to 3 s.f and also look at the figures in the question if they are upto 3 s.f then go for 3s.f.Hey people i have an important question.. Does number of significant figures matter in phy paper 2? If answer scheme gives 2sf for final answer but i gave in 3sf, do i lose any mark?
and also i need to know the speed of alpha and beta particlesCan someone please help me with qn 7 and please provide drawings if possible...
qn paper: http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s11_qp_21.pdf
ms: http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s11_ms_21.pdf
thanx soo much....
depends on the qn.....if u refer to mj/11 qp 21 , the sgf of the uncertainty in 1c.) is 1 sgf for the resistivity just lyk the resistance from the qn........so basically i am not sure but i think it's diff fr diff qnshow many significant figures do we have to give when calculating uncertainty?
First draw a rough right angled triangle(drawn in blue) and label the the hypotenuse base and height with their according speed, Now make a scale lets say 5m/s - 5boxes in the graph( I have used cms in my example). Now convert your velocities into box units,(which is basically 18m/s =18boxes) Now draw the right angled triangle again(drawn in red), this time on the graph and according to the box units. Then find the angle using a protractor( you can use trigonometry to make sure your angle measured is indeed correct)Please someone solve Q.4 d (i) and (ii)
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s07_qp_2.pdf
With explanation and diagram of-course. Thank you!
one complete cycle is 360 deg. so half a wave will be 180 deg. if you start second wave at half point of the first one, you create a phse difference of 180. a quarter you get 90 deg. a thisrd of the quarter and you get 30 deg phase difference. If you still don't get it ask me and I will explain with figures.please explain me how to make two waves in a same graph paper which have same phase angle eg 30 degree phase angle.how to make?
kindly explain with figures.one complete cycle is 360 deg. so half a wave will be 180 deg. if you start second wave at half point of the first one, you create a phse difference of 180. a quarter you get 90 deg. a thisrd of the quarter and you get 30 deg phase difference. If you still don't get it ask me and I will explain with figures.
Need help with Q2.
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w08_qp_2.pdf
Attempted this, looked at the mark scheme and I'd done it all wrong.
In the first part I did v2 = 2as. a = 9.81. s = 29.3m. The mark scheme says a = 0.85 and s = 12.8m.
They're asking for the speed BEFORE the brakes are applied so why do we need to use the values for when the car is skidding/decelerating?
Hope I'm making sense.
well, before the car was decelerating it was travelling at a constant speed, so you can't use the formula v^2 = u^2 + 2as for the distance 29.3m, because there was no accleration or change in speed during that period.
The constant speed of the car, which the question asks to find out, is the same as the initial speed of the car while decelerating, and the final speed is 0 m/s as the car comes to rest after deceleration. For this period the deceleration was .85g (given in question) and the car traveled a distance of 12.8 m before coming to rest. so you can use the v^2 =u^2 +2as formula here, where v= o , u= unknown, a= -.85g and s=12.8m
hope you got it!
Can someone please help me with qn 7 and please provide drawings if possible...
qn paper: http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s11_qp_21.pdf
ms: http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s11_ms_21.pdf
thanx soo much....
yup it sure did help tx a lotThe question says circular waves, so you have to use spherical dippers, and to observe interference the sources have to be coherent so the dippers have to be connected to the same vibrating source, the motor.
as for observing the pattern, you need a screen below the tank and a lamp above the tank.
here-
Hope this helps!
Oh, I see. So since both the thermistor and resistor + voltmeter have the same resistance, they get equal V.when the voltmeter has a resistance of 7800 ohm, the combined resistance in the parallel combination becomes (7800+7800)/ 2 = 3900 ohm ; as resistor R also has a resistance of 7800 ohm.
The thermistor has a resistance of 3900 ohm same as the total parallel combination , so the emf is divided equally between resistor R+ voltmeter and the thermistor. i.e. the emf is 1.5/2= .75 across each component.
Oh, I see. So since both the thermistor and resistor + voltmeter have the same resistance, they get equal V.
BTW, another question if you don't mind.
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s05_qp_2.pdf
Question 7 (c), I don't get this. Why can't the lower value of V give a lower power dissipation, since P = IV?
For almost 10 years, the site XtremePapers has been trying very hard to serve its users.
However, we are now struggling to cover its operational costs due to unforeseen circumstances. If we helped you in any way, kindly contribute and be the part of this effort. No act of kindness, no matter how small, is ever wasted.
Click here to Donate Now