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Maths, Addmaths and Statistics: Post your doubts here!

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ABC kitna hai ? 73 naa ..
AEC kitna hai 146 naa ?

Angle at center = 2 angle at circumference .. ye property bun rahi hai ??
AEC jo hai woh circle 2 kay ander hai .. hence Circle I ka center Circle 2 kay ander hai ..
point E small circle ka centre haI,
q k angle at centre is twice the angle at circumfernece ....
circumfenrce per 73 hai and centre per 146 that is double ..:)
E is not centre of small circle
Do properties aap nai state karni hain yahan
1. angle at centre is twice the angle at circumference so angle at centre will be 146(2*73)
2. angles subtended by an arc in the same segment of a circle are equal. so from any point on arc AC, the angle subtended will be 146, so the centre lies on arc AC
 
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E is not centre of small circle
Do properties aap nai state karni hain yahan
1. angle at centre is twice the angle at circumference so angle at centre will be 146(2*73)
2. angles subtended by an arc in the same segment of a circle are equal. so from any point on arc AC, the angle subtended will be 146, so the centre lies on arc AC
oh ha.. :)
 
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E is not centre of small circle
Do properties aap nai state karni hain yahan
1. angle at centre is twice the angle at circumference so angle at centre will be 146(2*73)
2. angles subtended by an arc in the same segment of a circle are equal. so from any point on arc AC, the angle subtended will be 146, so the centre lies on arc AC

wah bhai wah .. jo kaha sab sir kay ooper say guzar gaya :D
 
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Perimeter = 2 lines + arc small semi circle + arc large semi circle

2 lines = 40 cm
Small semi circle arc = 2pie x r x 1/2 x 1/4 = 5pie/2 r= 10
large semi circle arc = 2 pie x r 1/2 x 1/4 = 15 pie /2

perimeter = 40 + 10 pie = 71.4cm ..
ryt. .?
40 + 10 pie is enough :p THANKEW :)
 
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Pencils are packed in a box.
Each pencil has a diameter of 7 mm, correct to the nearest millimetre.
(a) Write down the lower bound of the diameter of a pencil.
Answer (a) ...............................mm [1]
(b) Find the smallest width of a box that can always hold 8 pencils side by side.
Give your answer in centimetres.
Answer (b) ................................ cm [2]

I need help in part (b)!!
 
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9
Pencils are packed in a box.
Each pencil has a diameter of 7 mm, correct to the nearest millimetre.
(a) Write down the lower bound of the diameter of a pencil.
Answer (a) ...............................mm [1]
(b) Find the smallest width of a box that can always hold 8 pencils side by side.
Give your answer in centimetres.
Answer (b) ................................ cm [2]

I need help in part (b)!!
this has been thoughroughly discussed some pages ago. wait i will post the link
 
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9
Pencils are packed in a box.
Each pencil has a diameter of 7 mm, correct to the nearest millimetre.
(a) Write down the lower bound of the diameter of a pencil.
Answer (a) ...............................mm [1]
(b) Find the smallest width of a box that can always hold 8 pencils side by side.
Give your answer in centimetres.
Answer (b) ................................ cm [2]

I need help in part (b)!!

(b) 8 x 7 for the width and then convert them to centimeter by dividing it by 10 !!
 
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9
Pencils are packed in a box.
Each pencil has a diameter of 7 mm, correct to the nearest millimetre.
(a) Write down the lower bound of the diameter of a pencil.
Answer (a) ...............................mm [1]
(b) Find the smallest width of a box that can always hold 8 pencils side by side.
Give your answer in centimetres.
Answer (b) ................................ cm [2]

I need help in part (b)!!
6 cm answer hai iska.. ??
 
Messages
1,074
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9
Pencils are packed in a box.
Each pencil has a diameter of 7 mm, correct to the nearest millimetre.
(a) Write down the lower bound of the diameter of a pencil.
Answer (a) ...............................mm [1]
(b) Find the smallest width of a box that can always hold 8 pencils side by side.
Give your answer in centimetres.
Answer (b) ................................ cm [2]

I need help in part (b)!!
they have asked for what? the smallest width that can ALWAYS hold 8 pencils, right? so we have to take the upper bound of the pencils's diameter. this is because if we take the lower bound of the pencils,6.5mm, the box could not hold 8 pencils if their actual diameter was more than 6.5 (which is totally possible) eg 7.5mm. what will happen then? the box could not hold 8 pencils. so in order for the box to hold the 8 pencils in ANY CASE, we will take upper bound of the diameter, ie 7.5mm
7.5mm*8 = 60 mm = 6 cm :)
 
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