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Q8bi)On a different note, please solve my probs . I have circled the parts I am facing problems in.
Number = moles * NA (Avogadro's constant) = (1.2/235) * 6.022 * 10^23 = 3.08 x 10^21
(ii) Let lambda = L
Activity = LN
N = No*e^(-Lt)
N(krypton) = 3.1*10^21*e^(-0.231*3600) = 0 so activity = 0
N(barium) = 3.1*10^21*e^(-6.4*10^(-4)*3600) = 3.1 * 10^20 <------ This many numbers left after one hour.
So Activity = 6.4*10^-4 * 3.1*10^20 = 2 x 10^17
Total Activity = 0 + 2 x 10^17 = 2 x 10^17