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Physics: Post your doubts here!

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Hey,

Could someone please show me how to work out the voltage and current across R1 and R2 respectively? Thanks!
M4jdDPk.png

Taking clockwise as the positive direction,
e.m.f = 1.5-1.5-1.5+1.5+1.5+1.5+1.5+1.5+1.5-1.5 = 6V

Total resistance = 1100 ohm

Current through R2 = V/R = 6/1100 = 5.5mA.

Voltage across R1 = (100/1100)*6 = 0.55V
 
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View attachment 54619
Why can't it be A??
A shows that velocity is increasing steadily, so constant acceleration so air resistance negligible right?
So why not A??

It cannot be A because the graph levels out, indicating constant velocity. If air resistance were negligible, the acceleration would always be equal to 9.81 m/s2 and the velocity would always be increasing constantly.
 
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It's a series circuit, so the current will be the same all around
Add up the emf of the batteries taking in note their directions
(so add up the ones facing one direction and subtract it from the others facing the other direction)

This gives total emf = 6V
Total resistance = 1000 + 100 ohms = 1100

Current = V/I
= 6/1100
= 5.5mA

V across R1 = I x R1
= 5.5mA x 100
= 0.55V

I across R2 = as I said earlier it's a series circuit, so the current is same in all components
= 5.5mA (as calculated above)
Taking clockwise as the positive direction,
e.m.f = 1.5-1.5-1.5+1.5+1.5+1.5+1.5+1.5+1.5-1.5 = 6V

Total resistance = 1100 ohm

Current through R2 = V/R = 6/1100 = 5.5mA.

Voltage across R1 = (100/1100)*6 = 0.55V

Thanks guys :)
 
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What happens when the time base on the C.R.O is doubled and the Y gain is unchanged? Should the frequency remain unchanged?
 
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If I scored 'd' in my AS levels, and I did pretty well in paper 4 and 5 (75/100 and 27/30), then what is the maximum grade that I can score? Can I get an A?
 
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