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The ammeter is reading the current in that line down there flowing through that resistor next to it. The resistor has potential difference V across it equal to that of the emf of the battery since it is a parallel circuit. The resistor also has its own resistance R. Both of these quantities do not change when the variable resistor's resistance increases. Therefore the current remains the same. Had the ammeter been placed in that branch with the variable resistor, the reading would have decreased.
But the fact that the overall resistance in the circuit increases, doesn't that change the current in the circuit?
The overall current in the circuit does decrease, but the effect is only on the portion with the variable resistor. Since it is a parallel circuit, the current in the two parts of the circuit will not necessarily be same.
The current next to the battery is the sum of the currents in the two branches. THIS will decrease. Because the branch with the variable resistor has less current.
why did u bring me here ?
I thought u had to check xPwhy did u bring me here ?
noooooHahah u got an alert that i hve to check?
Yes and the decrease in share of I to the section with variable resistor is the same as the decrease in overall I. So there is no effect on the ammeter reading.
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