Physics: Post your doubts here!

[Llamas]

Q15
not only did container X lose half the height even the mass became half
so m now will be m/2
and h will be h/2
g stays the same
we now have mgh/4

Q25 N lines per metre means 1/N and then substituting into the equation it will be (1/N) sin (theta)= n ( lambda)
sin theta/lamda is also = sin theta/((1/N) sin (theta)/n) solving it further gives Nn (if you don't know how to solve further let me know)



Q29 v^2 = 2as
a=F/m
F= EQ means Ee as in the question
so v^2=2*(Ee/m)*s
v^2/2=(Ee/m)*x
making x the subject
(v^2/2)/(Ee/m)=x
which equates to x=v^2*m/2Ee

Thank you so much, this was really helpful!

 

[Llamas]

Thanks again, I keep overlooking small details and bothering you.

28)
F= Eq
F = 3 x 10^7 x 1.6 x 10 ^(-19)
F = A

 

[Zepudee]

http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_w06_qp_4.pdf
Thought blocker thanks!

 

[Zepudee]

im sorry it is upside down but can you do the part (c) about the mean kinetic energy. the answer is just below the question Thought blocker

 

[Thought blocker]

Zepudee I will do it some other time. I am busy right now. I am sorry.

 

[Thought blocker]

Thanks again, I keep overlooking small details and bothering you.

No problem.

 

[Zepudee]

Zepudee I will do it some other time. I am busy right now. I am sorry.

boohoooo, alright!

 

[Thought blocker]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w06_qp_4.pdf
Thought blocker thanks!

Well oscillations, I hate it.
Till I know your answer is correct. But not sure, ask this to your teacher.
https://www.xtremepapers.com/commun...st-your-doubts-here.9860/page-591#post-850004 <--- MAybe correct.
And your other post, pic isn't loading. Re post it else tell me what it is.

 

[Zepudee]

to find the mean kinetic energy Thought blocker the answer is just below the question. Heh heh heh

 

[Zepudee]

i dont understand whyyy why 6R? Thought blocker

 

[Thought blocker]

Zepudee Images are not loading. :/

 

[Zepudee]

Zepudee Images are not loading. :/

boohoo, then it is alright, thanks for your effort. i appreciate it, really

 

[Thought blocker]

boohoo, then it is alright, thanks for your effort. i appreciate it, really

Which paper you have doubt in?

 

[Zepudee]

http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_s07_qp_4.pdf

This? hee, question 1(b). i know the GMm/2R and GMm/3R why is it 6R?

 

[Thought blocker]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s07_qp_4.pdf

This? hee, question 1(b). i know the GMm/2R and GMm/3R why is it 6R?

Lol! Seriously you don't know?
LCM!
(3GMm - 2GMm)/(2R x 3R) = GMm/6R.

 

[Zepudee]

Lol! Seriously you don't know?
LCM!
(3GMm - 2GMm)/(2R x 3R) = GMm/6R.

oh my gosh, my brain is getting rusty. gee... thanks...

 

[The Godfather]

Application NOTES NEEDED!

 

[akshay 999]

can someone help me out wiz ziz question plz.

An early experimenter, working in other than Si units, obtained the following ten values for the magnitudes of the changes on small oil drops:
9.82, 19.64, 39.28, 39.28, 34.37, 19.64, 19.64, 29.46, 19.64, 39.28.
What value do these results suggest for the magnitude of the charge of the electron as measured in these units?
A 2.45
B 4.91
C 9.82
D 19.64

 

[Llamas]

AND Question 16!

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s11_qp_11.pdf

Question 15 please!

 

[Thought blocker]

AND Question 16!

Click here, I have solved it before as well.