Physics: Post your doubts here!

[Asad Moosvi]

let the distance of one-side of the flight be s
for going: speed = s/t1= 600 so t1=s/600
for coming back: speed = s/t2 = 400 so t2 =s/400
now if we find overall speed as total distance/total time = 2s/(s/600 + s/400) = 2s/(s/240)=480km/h

Thank you, bro!

 

[ahmed faraz]

11)
theta as 0
The tension in the rope needs to balance out the weight of the student acting downwards, so since the total tension needs to be opposite and equal to the weight, Let tension in rope on left side be T1 and the tension on rope on right side T2 and :. Total tension = T1sino + T2sino
add them up... W= 2Tsino, rearrange to get T= W/ 2sino. Answer: B

14)
find the hypotenuse force 1st.
200/sin30. that will give u 400N.
Then 400*1.5 gives 600J.
Add frictional force and u get 750J.

14 with elaboration plz

 

[Suchal Riaz]

ok bye

 

[Thought blocker]

14 with elaboration plz

14)
First of all we will find the hypotenuse, sinθ = O/H so H = O / sinθ so H will be 3 m
so 200sin30 = 100
so F = 100+150 = 250
now W.D = F.s = 250 * 3 = 750 J

 

[ahmed faraz]

14)
First of all we will find the hypotenuse, sinθ = O/H so H = O / sinθ so H will be 3 m
so 200sin30 = 100
so F = 100+150 = 250
now W.D = F.s = 250 * 3 = 750 J

:****** !! Gd Luck I m Leaving thnx man ! Pray for Mee too

 

[AhsanAfzal]

http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_w02_qp_1.pdf
Q22 do we have to learn these?

 

[Thought blocker]

:****** !! Gd Luck I m Leaving thnx man ! Pray for Mee too

 

[Thought blocker]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w02_qp_1.pdf
Q22 do we have to learn these?

Yes...
Learn all this :¬

 

[Thought blocker]

All the best :** Do well Take care, bah bye

 

[Thought blocker]

Could You Provide me With Latest Estimates ? Thnx Man

I already did it

 

[Thought blocker]

Kal kitne baje paper hain ?

 

[Jelleh Belleh]

http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_s06_qp_1.pdf
Q 12 & 25 please?

 

[ahmed faraz]

I already did it

Just Typed It same time !

 

[ahmed faraz]

Kal kitne baje paper hain ?

12:00 GMT

 

[Thought blocker]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s06_qp_1.pdf
Q 12 & 25 please?

12)
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
initial momentum is (m)(-2v) + (3m)(v) as they;re travelling in opposite directions. total initial momentum = 3mv-2mv = mv
after collision, both stick hence the masses added, momentum after collision = (4m)(V)
initial = final
mv = 4mV
V = mv/4m both the *m* cancelled out, so V = v/4

25)
f=500Hz V=340m/s
V=f λ
so, lambda comes 0.68m
one wavelength means 360 ⁰ i.e, 2π
unitary method,
0.68 : 2π
0.17 : X
so, X = π/2

 

[Thought blocker]

12:00 GMT

Indian time batao na

 

[Thought blocker]

Just Typed It same time !

Coincidence do exist

 

[Jelleh Belleh]

12)
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
initial momentum is (m)(-2v) + (3m)(v) as they;re travelling in opposite directions. total initial momentum = 3mv-2mv = mv
after collision, both stick hence the masses added, momentum after collision = (4m)(V)
initial = final
mv = 4mV
V = mv/4m both the *m* cancelled out, so V = v/4

25)
f=500Hz V=340m/s
V=f λ
so, lambda comes 0.68m
one wavelength means 360 ⁰ i.e, 2π
unitary method,
0.68 : 2π
0.17 : X
so, X = π/2

Thanks so much!!

 

[Thought blocker]

kal India me kitne baje paper hain ?

 

[Jelleh Belleh]

kal India me kitne baje paper hain ?

Check your statement of entry.