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Well I considered both of the distance.
Extension is proportional to length but here it is compression so length will decrease hence inversely proportional.http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w11_qp_13.pdf
May someone explain question 25 to me quick? I have to do other questions too :/
Extension is proportional to length but here it is compression so length will decrease hence inversely proportional.
5)http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w13_qp_12.pdf Q5 , 7 ,8 ,11 and39 please help
Mass in Kg...q13 please
JAZALKAllAH KHAIR. Q15 bhi bta dien pleaseMass in Kg...
so
m1v1 = (m1+m2)v2
2.5 = 0.11v
v = 22.72 ≈ 23 m/s
Take moments from da hinge, let F b da reaction force of da spring.JAZALKAllAH KHAIR. Q15 bhi bta dien please
How 2 amplitudes and then 1 ? ?
Is it given in book ._- ?
I am not good at explainingSuppose light goes from the source L, it has an amplitude A (suppose). Then, some waves pass through the upper slit and some waves pass through the lower slit (on the diagram. In real life, this is a top-down view, so the slits are right next to each other horizontally).
The waves that pass through the upper slit (on the diagram) have amplitude A (diffraction doesn't change amplitude), and the waves that pass through the lower slit (on the diagram) also have amplitude A.
Therefore, the waves that pass through either slit have an amplitude of A. At the center of the screen S, one set of waves from each slit (one set from upper slit, one set from lower slit) overlap to form a central maxima. Since each of those sets has wavelength A, the superimposing constructive interference means that the waves at the center have amplitude A + A = 2A (since the waves at the center are in phase and so interfere constructively, their amplitudes add up).
So, the Intensity here is I. Since I = kA², we can write for this situation
I = k * (2A)²
I = k * (4A²)
I = 4kA²
So that k = I/(4A²).
This constant k remains the same for any particular wave, and since the wave does not change when one slit is blocked, this can be applied in the final condition as well.
In the final condition, only waves coming out of one slit reach the center. This set of waves has an amplitude of A, and since they do not interfere with themselves (and since there are no waves coming from the other slit to interfere with them), the final amplitude in this final situation is equal to A.
We again write, using I = kA² for this situation,
I(final) = k * (A²)
Since k = I/(4A²), we put this value into the equation above to get
I(final) = I/(4A²) * (A²)
I(final) = I/4 = D.
Hope this helped!
Good Luck for all your exams!
11)
No you are justI am not good at explaining
w12_12
5)
Simple concept, use your brain
19)
Use Pressure = force / area and find force ( dont forget to keep basic units of area )
Then w.d = f x d = A ( distance in meter)
27)
30)
Apply d*sin thetha = n*lamida
d = 1/n where n is no. of line/m. Metre not millimetre.
Grating's got 300lines/mm. So this means it has 300*1000 lines/m
(Coz 1m = 1000mm)
d = 1/n ie 1/300,000
U wanna see all the maximas possible, so to get max. no. of maximas on one half of the screen, u put thetha = 90
lamida is given. Convert it into m from nm.
U get n = 4
This means 4 maximas on one half of the screen.
On whole (both halves) of screen, maximas are = 4*2 = 8
BUT, u also have to consider the central maxima.
So total maximas are 8+1 = 9
36)
This is also a concept, we dont have fix values of currents, it varies, so we took a mean of power :¬
Find power at -1 and then at 2
For -1 :
P = 100W
For 2 :
P = 400W
Now as current is varying we have to take mean value of power : i.e 400 +100 = 500 / 2 = 250W
38)
remember when two resistor are in series, more voltage drop is at resistor with more value, so their a flashing light then R = 5 mega ohm when dark, then 5M is very large than 1 K of other resistor, then almost all voltage drop at 5M, hope you get this, it is a very simple concept.
But they said extra compression. samajh nae ayaTake moments from da hinge, let F b da reaction force of da spring.
15)
F × 2 = (40 × 9.8) × 5
2F = 1960 N
F = 980 N
------------------------------------
k = 10 kN/m = 10 000 N/m
k = F/x
x = F/k
x = 980/(10 000)
x = 0.098 m now convert it to cm i.e is 98 cm.---> C
Subtract p from q and add their uncertainity!! 1.27-.83=.44A quantity x is to be determined from the equation
x = P – Q.
P is measured as 1.27 ± 0.02 m.
Q is measured as 0.83 ± 0.01 m.
What is the percentage uncertainty in x to one significant figure?
A 0.4 % B 2 % C 3 % D 7 %
That is what we foundBut they said extra compression. samajh nae aya
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