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http://papers.xtremepapers.com/CIE/...and AS Level/Physics (9702)/9702_s08_qp_2.pdf
can someone help question 6 b please!
can someone help question 6 b please!
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u're welcumThanks
Thanks to ZaqZainabhttp://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s08_qp_2.pdf
can someone help question 6 b please!
Thanks to ZaqZainab
when S2 is closed the "path of least resistance" will take up most of the current
so the current would flow through S2 rather than through B cause here B has resistance
for (i) we use power= VI
we don't have I so we replace I with V/R which we take from the equation R=V/I
power=v^2/r
R=38.4
ii) they are talking about total poser
so if S1 open there is no power you get this one right because the circuit is not complete
S1 and S2 closed as i said current always takes easier path so it will not go through B so in P=IV I=O the P is also 0 for B but then the current flows through A so its 1.5k+0=1.5k
if all of them are closed here again we will take power of B as 0 and if you see we have A and C in parallel Total power=P1+P2......... SO 1.5+1.5
S1 is closed so so we have A and B in series 1/total power = 1/p1 + 1/p2 +............
so 1/total power= 1/1.5 +1/1.5
total power =0.75
here s1 and S3 are closed so we have A and B parallel to C ie (AB) parallel to C for parallel Total power=P1+P2.........
and we already found AB which is 0.75 so now we just need to add 1.5
Thought blocker's explanation is correct but the proportionality of P to V2 wasn't mentioned so to just highlight that i still intended to post this ....http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s08_qp_2.pdf
can someone help question 6 b please!
NpThought blocker's explanation is correct but the proportionality of P to V2 wasn't mentioned so to just highlight that i still intended to post this ....
I am online from tab, and it will take a lot time to reply, and I have to finish M1 so please help her asapcan anyone help me out with explanations ?
View attachment 38531
View attachment 38529 View attachment 38530 View attachment 38532
17 would be A cause if you complete the lines of the force acting all should intersect at the same pointcan anyone help me out with explanations ?
View attachment 38531
View attachment 38529 View attachment 38530 View attachment 38532
Feels honoredThanks to ZaqZainab
when S2 is closed the "path of least resistance" will take up most of the current
so the current would flow through S2 rather than through B cause here B has resistance
for (i) we use power= VI
we don't have I so we replace I with V/R which we take from the equation R=V/I
power=v^2/r
R=38.4
ii) they are talking about total poser
so if S1 open there is no power you get this one right because the circuit is not complete
S1 and S2 closed as i said current always takes easier path so it will not go through B so in P=IV I=O the P is also 0 for B but then the current flows through A so its 1.5k+0=1.5k
if all of them are closed here again we will take power of B as 0 and if you see we have A and C in parallel Total power=P1+P2......... SO 1.5+1.5
S1 is closed so so we have A and B in series 1/total power = 1/p1 + 1/p2 +............
so 1/total power= 1/1.5 +1/1.5
total power =0.75
here s1 and S3 are closed so we have A and B parallel to C ie (AB) parallel to C for parallel Total power=P1+P2.........
and we already found AB which is 0.75 so now we just need to add 1.5
Genius17 would be A cause if you complete the lines of the force acting all should intersect at the same point
View attachment 38547
24 you are given the spring constant the firmula for spring constant is K=F/e
where K is the spring constant F is the force and e is the extension
as the trolley is that rest the force applied by P = force by Q
Force by P=k*e=60*0.40=24
Force by Q=k*e=120*e=24
e=24/120=0.2
15. the viscous force in the starting is 0 and it keeps increasing until the body comes to rest so the answer is not A
The upthrust would stays the same
thanks a lot help me can you please help me with other questions?Anzuman turin View attachment 38549
this isnt perfectly drawn but yeah it would be something like this
1 loop -fthanks a lot help me can you please help me with other questions?
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