- Messages
- 6,440
- Reaction score
- 31,077
- Points
- 698
can someone help me with these questions?
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s09_qp_1.pdf
10 20 25 and 29
10) conservation of momentum = momentum b4 and after are always equal.
So, since b4 the split, the momentum = 0...hence after the split the total momentum shud also =0 ----> the momentum if both the particles shud be the same (as they moce in opp direction,the momenta cancel each other out).
So, since one particle has mass = 2m, the other will have velocity = 2v.
So, the momentum wud be 2mv for both.
Now, for K.E. we square the velocity.
So, particle 1, mass = m. velocity = 2v. so K.E. = 1/2 * m * (2v)^2 ------> 2mv^2
particle 2, mass = 2m. velocity = v. so K.E. = 1/2 * 2m * v^2 -----> mv^2
ratio = 2: 1
Hope i helped.
All credit to Nibz