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Physics: Post your doubts here!

Tkp

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guys can anyone explain me question 6 (c) ?

6 c) Energy = 5.7 * 10^3 eV ---> convert the eV into Joules
1 eV = 1.6 * 10^-19 J
So, 5.7 * 10^3 eV ----> (5.7 * 10^3) * 1.6 * 10^-19 = 9.12 × 10^–16 J

So, kinetic energy = 9.12 × 10^–16 J
Kinetic energy = 1/2 * m * v^2
9.12 × 10^–16 = 0.5 * (9.11 * 10^-31) * v^2

So, v^2 = (9.12 × 10^–16) / (0.5 * 9.11 * 10^-31)
v = 4.47 * 10^7 m/s

Hope u gt it!!!
:LOL:
 
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EtKLvmD.jpg


plzzzzzzzzz explain!!!!!!!!!!!
 
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What is the phase difference between these two points? :(
Pls help
 

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any help ? qn 6 (b) and (c) i and iv .....
isnt it 90 degree ? in MS it shows zero rad! and what does the sign in last question mean
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s11_qp_23.pdf
Tkp


In stationary wave.. Particles in the same segment/ between 2 adjacent nodes, are in phase. Particles in adjacent segments are in anti-phase.


While In Progressive wave.. All particles within one wavelength have different phases.

bii ) 180 degrees.. since it's progressive and half wavelength apart.

ci) 0 degrees.. since it's a stationary wave and both are in the same segment.

iv.. it is just a variable.. which doesn't matter..

If the wave given has time period x.. you need to draw a wave with 0.25x time period.. As F=1/T F=1/0.25 simple draw a wave with 4 times the frequency... but same amplitude.
 
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