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use first harmonic and second harmonic for a fixed length of string:Why is the answer C:-
View attachment 22234
Hi everyone, AsSalamoAlaikum Wr Wb...
To get things organized in a better way, I am making this thread. As othewise, some queries remain unanswered!
So post your PHYSICS doubts in this thread. InshaAllah other people here will help me and you all.
NOTE: If any doubts in the pastpapers, please post the link! You can find links here!
Any Physics related notes and links will be added here in this post. Feel free to provide the links to your notes around the forum, or any other websites!
Thanks!
Jazak Allah Khair!
Physics Notes:
Some links & Notes - by destined007
Physics Practical Tips - by arlery
Notes for A2 Direct Sensing (Applications) - shared by sweetiepie
Physics Summarised Notes (Click to download)
AS and A-Level Physics Definitions
A2: Physics Revision notes - by smzimran
Paper:5 Finding uncerainty in log - by XPFMember
Physics Paper 5 tips - by arlery
Physics Compiled Pastpapers: <Credits to CaptainDanger for sharing this..>
Here are the compiled A level topical Physics questions in PDF form...
Paper 1 : http://www.mediafire.com/?tocg6ha6ihkwd
Paper 2 & Paper 4 : http://www.mediafire.com/?g65j51stacmy33c
(Source : http://www.alevelforum.com/viewtopic.php?f=15&t=14)
the first 1 is fundamental.so the wavelength is 2l and f for the fundamental.Fr the second harmonic motion the wavelngth is l and the frequency is 2 l.Why is the answer C:-
View attachment 22234
f=kx(take extension in m)Why is the answer D:-
View attachment 22229
favg is the average forcecan u pls answer this questionAn insect of mass 4.5mg flying with a speed of 0.12m/s-1,encounters a spider's web which brings it to rest in 2.0ms .calculate the average force exerted by the insect on the web.this is an phy AS level question under momentum topic
ans is Cf=kx(take extension in m)
so 12/(100/1000).so the ans is c.
u r awe greatfavg is the average force
Favg * t = change in momentum
Favg * 2 * 10^-3 = mv - mu (v is final velocity u is initial velocity)
Favg * 2 * 10^-3 = 0 - 4.5*10^-3 * .12
now calculate for average force
ans is C
the answer of this is D not Cf=kx(take extension in m)
so 12/(100/1000).so the ans is c.
f=kxthe answer of this is D not C
the link that u have provide is fr marking schemehttp://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w05_ms_1.pdf
Mcq no. 21.
How do we solve it?!
damn.didnt see that it was 40 at first.the ans is df=kx
where 'x' is the change in length
k=f/x ; 12/(100-40)/1000 = 200Nm^-1
hehe thanks buddyu r awe great
well frequency is going to be same in both cases as frequency depends on the source now just plug in values in the equation v=fw(let w equal to wavelength)http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w05_ms_1.pdf
Mcq no. 21.
How do we solve it?!
well u have to know the formula.f=(dell p)/dell tcan u pls answer this questionAn insect of mass 4.5mg flying with a speed of 0.12m/s-1,encounters a spider's web which brings it to rest in 2.0ms .calculate the average force exerted by the insect on the web.this is an phy AS level question under momentum topic
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