Physics: Post your doubts here!

[yumichikabyakuya renji]

Post z question directly- Make a print screen

that took me quite a time, and then it said my pc does not have an allowed extension
how do u usually print screen?

 

[yumichikabyakuya renji]

okay look i am not sure about the SI unit thing, but area isn't a unit, a unit woud be someting yu write after a quantity, so for eg i can say 250kg, 300seconds, 500metres, but can i say 400areas? noo i can't......area is measured in metres.....not vice versa....hope you get it.....

omg! thXx!! now i got it thnk u vry much

 

[Soldier313]

that took me quite a time, and then it said my pc does not have an allowed extension
how do u usually print screen?

what computer do you use? if it's normal pc or laptop - there's a printscreen button on the right of the keyboard
if it's a mac - just press command + shift + 3
that's as far as i know

 

[Soldier313]

omg! thXx!! now i got it thnk u vry much

you are welcome

 

[yumichikabyakuya renji]

what computer do you use? if it's normal pc or laptop - there's a printscreen button on the right of the keyboard
if it's a mac - just press command + shift + 3
that's as far as i know

ya, this i did but my pc stores the image in .bmp,, i think to upload an image here .jpg is required what u usually do after prnt screen?

 

[Soldier313]

ya, this i did but my pc stores the image in .bmp,, i think to upload an image here .jpg is required what u usually do after prnt screen?

er...mine automatically stores in jpeg format so i don't get a pro
to convert from bmp to jpg, follow this link: http://www.pictureresize.org/online-images-converter.html
or this link: http://www.online-tech-tips.com/computer-tips/convert-bmp-to-jpg/

both show diff ways to do it

 

[yumichikabyakuya renji]

er...mine automatically stores in jpeg format so i don't get a pro
to convert from bmp to jpg, follow this link: http://www.pictureresize.org/online-images-converter.html
or this link: http://www.online-tech-tips.com/computer-tips/convert-bmp-to-jpg/

both show diff ways to do it

thXx thxx a million times, it worked

 

[Soldier313]

thXx thxx a million times, it worked

aww that's great!! you are welcome anytime

 

[yumichikabyakuya renji]

Post z question directly- Make a print screen

here

 

[queen of the legend]

i need help in question question 4c, may/june 2008 paper 2 asap pls
where did value of delta h come from ?!
http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s08_qp_2.pdf
mark scheme: http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s08_ms_2.pdf

 

[Dhaval Shah]

i need help in question question 4c, may/june 2008 paper 2 asap pls
where did value of delta h come from ?!
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s08_qp_2.pdf
mark scheme: http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s08_ms_2.pdf

In the method in the marking scheme isn’t it they calculated a value of h using pressure as 1.01 x 105 and they used the formula Pressure = height x g x density. Then the h they calculated (which is 9.53) they subtracted that from 10 (which is the value of h the divers are taking in the question) to find delta h, which is 0.47 then they proceed to find the uncertainty and get the question right

 

[mrnt3250]

Hey guys, I've got some mixed signals in doing Q 1 / part B of w02_qp_2.
I don't know why p/ro = m^-1 s^-2 / kg m^-3 which is equal to = kg^-1 m^-4 s^-2,
and then the marking scheme says square root of p/ro = ms^-1 <==== How?!?!?

QP: http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_w02_qp_2.pdf
MS: http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_w02_ms_2.pdf

Thanks in advance.

 

[raamish]

how do i do qs 2a(ii) The mark scheme is confusing me.
Link: http://www.xtremepapers.com/papers/...and AS Level/Physics (9702)/9702_s03_qp_2.pdf

 

[Dhaval Shah]

Hey guys, I've got some mixed signals in doing Q 1 / part B of w02_qp_2.
I don't know why p/ro = m^-1 s^-2 / kg m^-3 which is equal to = kg^-1 m^-4 s^-2,
and then the marking scheme says square root of p/ro = ms^-1 <==== How?!?!?

QP: http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w02_qp_2.pdf
MS: http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w02_ms_2.pdf

Thanks in advance.

I have no idea what you are saying but ill still try to explain Unit of Pressure is N(m^-2) right, since its force over area. Now N (newton) is kgm(s^-2) so P's base units are kg(m^-1)(s^-2). Now P/ro will be (kg(m^-1)(s^-2))/(kg(m^-3)) right? So the kg's get canceled out and since the m^-3 unit is at the bottom, when we take it to the top the -3 becomes +3 so the units would be (m^(-1+3))(s^-2) = (m^2)(s^-2) but we arent done since theres still the square root (which also applies to units) so the unit would be m(s^-1) x (the constant) and m(s^-1) is the unit of velocity, therefore the constant has no units.

 

[mrnt3250]

how do i do qs 2a(ii) The mark scheme is confusing me.
Link: http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s03_qp_2.pdf

Well, its relatively easy. Displacement is defined as the distance from a fixed point in a specified direction. We're all clear, right?
Let me give you an example:
I'm sitting in front of my computer and from this point, I will go out of the room and stop there. The distance between my initial position and the point I stopped at is my displacement. In reality, I'm still sitting in front of my computer typing this answer, which means I haven't moved, and my displacement is 0.

 

[mrnt3250]

Oct/Nov 2004, Paper2, Question 1, Part B) (ii)

I got the percentage uncertainty of diameter of wire as (0.02 / 0.50) * 100 = 4 %

Now when I try to get the uncertainty of the area of cross-section of the wire, the answer doesn't come up as 8%.

This is how I do it:
Cross-sectional area = pi * (r^2)
Diameter = 0.50 mm / 2 = 0.25 mm
pi (0.25^2) = 0.196 ~= 0.2 mm^2
% uncertainty of cross-sectional area = (uncertainty of area / area)* 100
% uncertainty of cross-sectional area = (0.02 / 0.2) * 100 = 10 % ????

Do I have to separately calculate the uncertainty of cross-sectional area? If yes, how?

QP: http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w04_qp_2.pdf
MS: http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w04_ms_2.pdf

Thanks in advance.

 

[Dhaval Shah]

Oct/Nov 2004, Paper2, Question 1, Part B) (ii)

I got the percentage uncertainty of diameter of wire as (0.02 / 0.50) * 100 = 4 %

Now when I try to get the uncertainty of the area of cross-section of the wire, the answer doesn't come up as 8%.

This is how I do it:
Cross-sectional area = pi * (r^2)
Diameter = 0.50 mm / 2 = 0.25 mm
pi (0.25^2) = 0.196 ~= 0.2 mm^2
% uncertainty of cross-sectional area = (uncertainty of area / area)* 100
% uncertainty of cross-sectional area = (0.02 / 0.2) * 100 = 10 % ????

Do I have to separately calculate the uncertainty of cross-sectional area? If yes, how?

QP: http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w04_qp_2.pdf
MS: http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_w04_ms_2.pdf

Thanks in advance.

All that working for the second part is completely unnecessary, its just for 1 mark! First of all you should know that the percentage uncertainty in r is the same as in the diameter (4%) as dividing or multiplying by a constant has no effect on uncertainty. Now Area = pie x (r^2), and pie is a constant so again that will have no effect on uncertainty. so we only need the r^2. Now when there are indices involved you have to multiply the uncertainty by the index (for example, uncertainty in r = 4%, so uncertainty in (r^2) is 4% x 2 = 8%, so if it was (r^3) like maybe volume or something, the uncertainty would be 4% x 3 = 12%) so in this case all we have to do is 4 x 2 which gives us 8%, that's it!

 

[mrnt3250]

May/June 2006 - QP2 - Q1) (c)(ii)

What is the procedures to solve this part of question?
I don't get it.

QP: http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s06_qp_2.pdf
MS: http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s06_ms_2.pdf

Thanks in advance.

 

[queen of the legend]

I cannot understand these two question: 4b and 5 all from may/june 2009 first variant paper 2
some1 explain pls

 

[queen of the legend]

how do i do qs 2a(ii) The mark scheme is confusing me.
Link: http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s03_qp_2.pdf

since displacemnt is distance covered in particular direction, when a car travels suppose from point A to B and goes back to A its total distance is AB + BA, but the DISPLACEMET is zero from point A. i hope u understand now !