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the activity A0 is stated with 2% error. we hav to get the time for 10% ka error. means original se 8% error. if original is A0, then after 8% error, it will be 0.92A0. we will consider the expression: A = A0* e^(-lambda*time)Assalamu alaikum,
Can you please explain how to solve Q.9?? thanks!
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s09_qp_4.pdf
here's the marking scheme;
http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Physics (9702)/9702_s09_ms_4.pdf
thanks! btw I was asking about Q.6 and it got mistyped. Can you solve that one too, about electromagnetism??the activity A0 is stated with 2% error. we hav to get the time for 10% ka error. means original se 8% error. if original is A0, then after 8% error, it will be 0.92A0. we will consider the expression: A = A0* e^(-lambda*time)
lambda will be 0.693/half life
lambda = 0.693/(5.27*365*24*3600)
A = 0.92 A0
so the equation will be:
0.92A0 = A0 * e^(-lambda*time)
A0 will be cancelled
0.92 = e^ (-lambda*time)
ln (0.92) = -lambda*time
part b and c??which part of q6?
bi) reading on balance is increasing which means force on balance is acting downwards. according to newton's third law, every action has an equal and opposite reaction. so the wire will have force upwards with the same magnitude. the direction of current in from X to Y and the force is upwards. according to fleming's rule, magnetic field is from ryt to left so pole P is north cox magnetic field is directed from north to southpart b and c??
bii) B = F/(IL)part b and c??
waeyyakum..Thanks A lot Bro
JazzakAllah
AoA,Assalamoaalikum wr wb!
some doubts in Nov 2005 Paper 4 Physics...
· Q:3 I’m sorta confused with the calculation...part b ...and I don’t understand why they give the ans to C to 2s.f when they’re penalising 2s.f in part b?
· Q:4 c Why speed max when displacement is zero? :s
· Q:5b(ii) why when speed is reduced, deflection is larger? :s
· Q:6 b I don’t understand
AoA,Assalamoaalikum wr wb!
some doubts in Nov 2005 Paper 4 Physics...
· Q:3 I’m sorta confused with the calculation...part b ...and I don’t understand why they give the ans to C to 2s.f when they’re penalising 2s.f in part b?
· Q:4 c Why speed max when displacement is zero? :s
· Q:5b(ii) why when speed is reduced, deflection is larger? :s
· Q:6 b I don’t understand
Electric field stregth = Voltage / Distance between the platesQ2? AND
how to find the magnitude in Q 6A 1?
AoA,Assalamoaalikum wr wb!
some doubts in Nov 2005 Paper 4 Physics...
· Q:3 I’m sorta confused with the calculation...part b ...and I don’t understand why they give the ans to C to 2s.f when they’re penalising 2s.f in part b?
· Q:4 c Why speed max when displacement is zero? :s
· Q:5b(ii) why when speed is reduced, deflection is larger? :s
· Q:6 b I don’t understand
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