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and here are complete and precise BIOLOGY NOTES that contain ATP procedures as well
http://www.mediafire.com/download.php?fd5s1c9s6z6a8n3
http://www.mediafire.com/download.php?fd5s1c9s6z6a8n3
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this gradient shows us conductance. so d might be the right option as it shows higest conductance i.e lowest resistance.the concept behind it too View attachment 6341
u r asking same questions again and again. i have already answered these. type the confusion in the respective mcq.PAPER 1 OCT/NOV 2010 /11
I need help with Q)13,18,19,24,33,34
http://www.xtremepapers.com/CIE/International A And AS Level/9702 - Physics/9702_w10_qp_11.pdf
what's dre to waoo about?waooo...:
27) its zero because the distance moved by the unit positive charge is not in the direction of the force applied. the force here is towards the centre. centripetal force. what say?Guyz can ne1 help me with these Q
http://www.xtremepapers.com/CIE/International A And AS Level/9702 - Physics/9702_s10_qp_11.pdf Q no 27, 29
27) its zero because the distance moved by the unit positive charge is not in the direction of the force applied. the force here is towards the centre. centripetal force. what say?
29)direction of field is INTO the paper. u need to make 3D view in your mind. its coming out of the paper from positive to negative. when electron beam travels from left to right, it will come out of the paper into the observer eyes.
your welcomeThnks Mate.
man the answer is -5.76 !!!http://www.xtremepapers.com/CIE/International A And AS Level/9702 - Physics/9702_s09_qp_02.pdf
Q.2 part b(i)
isn't the change in momentum suppose to be mv-mu?
I can't solve part b(i), please help!
My answer comes out to be -57.6, its supposed to be +57.6
this is so messy. can u please upload the links and write clearly. thankshave some doubts in paper 1 m/j 05 q14, o/n 05 q5,7,16, o/n 09 q9,14,28, m/j 10(P11) q22,26,27, o/n 10(P11) q18,24,37, m/j 11(P11) q15,34
this is so messy. can u please upload the links and write clearly. thanks
But the marking scheme states it to be +57.6man the answer is -5.76 !!!
very simple: mv-mu = change in momentum. 1.2 ( -0.8 - 4 ) = -5.76 kg m/s , u shud notice the time of collision. the initial velocity being 4 m/s and final being -0.8 .
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