Physics: Post your doubts here!

[farhan143]

Here's the solution:

Thank you so much !!
such a relief....

 

[farhan143]

Doubt in :
Question no 4(d) vector diagram 2007 may/june., paper 2

 

[rz123]

Doubt in :
Question no 4(d) vector diagram 2007 may/june., paper 2

hi, i think it will be done like this : horizontal component of velocity and vertical component of velocity are perpendicular to each other. choose a scale like 1 cm represent 5 m/s. draw a horizontal line indicating horizontal velocity similarly draw a vertical line indicating vertical velocity which is 25.3 m/s. in order to draw the resultant u need to apply parallelogram method or triangle rule. clear?

 

[leadingguy]

use simple formulas and definations here which u can easily fing on aplication support booklet page 22 here is the link
http://www.xtremepapers.com/CIE/ind...ysics/&file=9702 Applications Booklet WEB.pdf

 

[ABDSyed]

Plz Can anyone help me with M/J2005 P1 Q4
I am getting uncertainty 2.25% but the answer Say its 0.4%

 

[leadingguy]

Plz Can anyone help me with M/J2005 P1 Q4
I am getting uncertainty 2.25% but the answer Say its 0.4%

itx simple bro.
v=s/t so v= 16.oms-1 (we will not take 16.00ms-1 as the speed bcz the value of distance is till one significant figure)

now to calculate uncertainity in speed

delta v/V = [delta d/d + delta t/t ]

delta v/V = [0.1/40 + 0.05/2.50]

delta v/V = [9/400]
now dlta v = (9/400) * V ......................... (9/400)*16 = 0.36

remember that distance is till one decimal place so we wil convrt our all ans to one decimal place so rond of 0.36 to 0.4


now ur ans is 16.0+- 0.4 ms-1 (a little logical )

 

[JD REBORN]

Q 24 of p1 May June 2008 and Q18 of may june 2009 with proper explanation.

 

[ABDSyed]

itx simple bro.
v=s/t so v= 16.oms-1 (we will not take 16.00ms-1 as the speed bcz the value of distance is till one significant figure)

now to calculate uncertainity in speed

delta v/V = [delta d/d + delta t/t ]

delta v/V = [0.1/40 + 0.05/2.50]

delta v/V = [9/400]
now dlta v = (9/400) * V ......................... (9/400)*16 = 0.36

remember that distance is till one decimal place so we wil convrt our all ans to one decimal place so rond of 0.36 to 0.4


now ur ans is 16.0+- 0.4 ms-1 (a little logical )

THnx Bro

 

[Silent Hunter]

http://www.xtremepapers.com/CIE/ind... Level/9702 - Physics/&file=9702_s07_qp_1.pdf

help needed in Q12 ? Thank you

 

[smzimran]

http://www.xtremepapers.com/CIE/index.php?dir=International A And AS Level/9702 - Physics/&file=9702_s07_qp_1.pdf

help needed in Q12 ? Thank you

According to the law of conservationof momentum,
m1v1 + m2v2 = (m1+m2)V
2*4 + 4*1 = (2+4)V
V= 2 m/s
Now,
Total energy after collision = 1/2 (m1+m2) (V^2)
= 1/2 (6) (2^2)
= 1/2 (6) (4)
= 12 J
So, B is the answer.

 

[leadingguy]

Re: Physics questions? please?

Question 10 Please.

Thanks!

u can easily learn the formulas and definations being asked in this question from the application support booklet on page 22! its in detail and easy chek it.

 

[Silent Hunter]

http://www.xtremepapers.com/CIE/ind...Level/9702 - Physics/&file=9702_s10_qp_11.pdf

Q13 AND 11 THANK YOU

 

[maybeitwasnoone]

http://www.xtremepapers.com/CIE/index.php?dir=International A And AS Level/9702 - Physics/&file=9702_s10_qp_11.pdf

Q13 AND 11 THANK YOU

11 is C. Using F=ma, where F is the resultant force So, F would be 10-4 and m would be 20/10=10, substitute these values to find a.

 

[Silent Hunter]

 

[Silent Hunter]

11 is C. Using F=ma, where F is the resultant force So, F would be 10-4 and m would be 20/10=10, substitute these values to find a.

wont 20/10 = 2 ?

 

[maybeitwasnoone]

wont 20/10 = 2 ?

My bad, sorry. You're right. You get the right answer with 6/2=3 don't you?

 

[maybeitwasnoone]

View attachment 4862

Is the answer A?

 

[Silent Hunter]

Is the answer A?

answer is D

 

[1357913579]

http://www.xtremepapers.com/CIE/index.php?dir=International A And AS Level/9702 - Physics/&file=9702_s10_qp_11.pdf

Q13 AND 11 THANK YOU

first of all regarding no. 11 f=ma the weight of the substance is 20kg an its mass is 2 as g=10 in this case
two forces in opposite direction so 10-4=6
6=ma
6=2a
a=3
regarding 13
first thing what could be the minimum value of cos its o when all the forcse all prependicular to each other so by resolution when all forcse will get 0 as cos will get 0 so A is the answer
if you still have a confusion do tell me

 

[OakMoon!]

View attachment 4862

Total work done= Work done against friction+Work done to increase the Potential Energy
=150*1.5/sin30+200*1.5
=450+300
=750J (D)