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thankyou so muchThe increase in current suggests that the total resistance of the circuit increased(R=V/I). Now the only way the resistance can increase is through the variable resistor. So the resistance of the variable resistor was increased, and you can determine how much pd it takes up using the potential divider formula,(r1/r1+r2)*Vtotal. You can use some values to figure out that the pd of the variable resistor would increase while pd for fixed resistor would decrease. So the voltmeter readings on Q increase and for P it decreases(B).
I answered this a couple of days ago, so just gonna copy paste my previous explanation:The three forces acting on a hot-air balloon that is moving vertically are its weight, the force due to air resistance and the upthrust force. The hot-air balloon descends vertically at constant speed. The force of air resistance on the balloon is F. Which weight of material must be released from the balloon so that it ascends vertically at the same constant speed?
A F
B 2F
C 3F
D 4F
Welcomethankyou so much
37 C?These are two very tough questions if you wanna practice.
It's D37 C?
Diffraction grating maxima are more spread because there are so many slits in grating than double slit, so more diffraction takes in grating hence creating more widely spread maxima. D grating maxima are sharper because again, there are so many slits in grating compared to the two in double slit, so more diffraction takes places so more waves can interfere and create a large amplitude(meaning sharper).
Yeah the answer is C. Just apply kirchhoff's 2nd lawans is C?
How?It's D
23: maximum pressure point is compression while minimum pressure point is rarefaction. The distance between rarefaction and compression is half the wavelength. Using v=flamda, find the wavelength and divide it by 2 to get the distance between rarefaction and compression. Wavelength will turn out to be 0.6m, so the answer is 0.3m(B).
27: you see that there is half a loop and it's a fixed string experiment. So in v=flamda, the lamda will be 0.5 which will make the equation v=0.5flamda. Now, if you want a complete wave, you would need to make the equation v=f(lamda). You can do this by increasing the frequency by 2 so that the 0.5 is cancelled out. Hence 2f is the answer(C).
28: d=1/N ---> d=1/300x1000
dsintheta=nlamda
1/300x1000 *sin90=n(600x10^-9)
n=5
This means that there are 5 orders above the central maxima and 5 below. So including the central maxima there is a total of 11 maxima(5+1+5). So the answer is C.
25: There are two sections to this question. First the train approaches the observer then the train goes away from the observer. They are asking you to find the difference in oib
Thankyou... I wasn't multiplying the moments by 2.
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