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Physics: Post your doubts here!

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June 12 P41
7c
why does the force vary at twice the frequency of current? it says it will vary by sin^2 x
The magnitude of attractive magnetic force between the wires depends on the product of the currents and inversely on the distance between these two currents....product of currents = I^2 = sinosoidal and in phase ...thus f of the force varies by 2f of the current
 
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First find the weight of the object:
W = mg = 5.09 * 9.81 = 49.9N

Then find it's base area : pi * r^2 = pi * (9.4/2 * 10^-2)^2 = 6.939 * 10^-3 m^2

So pressure will be,
P = F/A
Here force exerted is the weight, so
P = 49.9./6.939*10^-3
= 7195
~7200 Pa
can u just explain this base area thing again? :/
 
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tht complete which i pasted..like its pi*r^2..ryt? so why is 9.4 divided by 2? :confused::confused::censored::censored::giggle:
You are given diameter, so first you'll have to convert that to radius by halving it. Then you are to convert this radius into meters, since the diameter you are given is in centimeters, because if you are not giving to convert you can never get answer in pascals! Get it?
 
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