Physics: Post your doubts here!

[Komail Sabba']

P4 Oct 2008 Question 1b(2)
Anyone could explain please?

 

[Bilal Khan]

P4 Oct 2008 Question 1b(2)
Anyone could explain please?

post the question properly.

 

[yoyoyoyoyoyoyoyoyoyo]

s13 p42 q12 b(i) and q8 b(iii) ? anyone pls ?
http://maxpapers.com/wp-content/uploads/2012/11/9702_s13_qp_42.pdf

 

[Abdul Hanan]

Ok

you are added.... check the convo

 

[TheJDOG]

P4 Oct 2008 Question 1b(2)
Anyone could explain please?

There is no acceleration at the poles of the Earth. So 0.

 

[papajohn]

Please make me correct. I dunno that i make it right.
It is question Q7 b(ii)..
http://maxpapers.com/wp-content/uploads/2012/11/9702_s14_ms_41.pdf

 

[Ancordi Ashley zakia]

Can anyone please post the guess papers for physics paper two???????

 

[Ancordi Ashley zakia]

Where are the guess papers please????

 

[nehaoscar]

Anyone did p2 variant 22 today?

 

[Llama2617]

meee how did you find it. I found it quite difficult

 

[My Name]

Can someone help me with this question

http://studyguide.pk/Past Papers/CIE/International A And AS Level/9702 - Physics/9702_s09_qp_4.pdf

Question 1 part c (ii)

Can’t I use the formula for orbital speed which is:

Btw the mark scheme says

 

[Wolfgangs]

Can someone please help me with this graph?

 

[F.Z.M. 7]

Can someone please help me with this graph?

lower the amplitude a bit but not very much as the graph goes on
everything else same

 

[_Ahmad]

can any one please explain question 2 (a) of this paper
http://freeexampapers.com/A-Level/Physics/CIE/2003-Jun/9702_s03_qp_4.pdf

 

[TheJDOG]

Can someone help me with this question

http://studyguide.pk/Past Papers/CIE/International A And AS Level/9702 - Physics/9702_s09_qp_4.pdf

Question 1 part c (ii)

Can’t I use the formula for orbital speed which is:
View attachment 53668
Btw the mark scheme says
View attachment 53669

Hey, no because in this case, the rock is falling straight so it has a straight speed , you can't use Vorbit here, it's not moving in circular motion. We know that Energy= m( change in potential)
But here the energy is Kinetic, so 1/2mv^2=m(change in potential)
Cross m and work for v.
So v= 5.5 x 10^3 m/s

 

[mehria]

http://maxpapers.com/wp-content/uploads/2012/11/9702_w14_qp_42.pdf

Q 5 (b) (ii)

 

[mehria]

Can someone please help me with this graph?

 

[mehria]

see solution 619 at
http://physics-ref.blogspot.com/2015/04/physics-9702-doubts-help-page-122.html

thnk u so much...

 

[mehria]

see solution 619 at
http://physics-ref.blogspot.com/2015/04/physics-9702-doubts-help-page-122.html

http://maxpapers.com/wp-content/uploads/2012/11/9702_w14_qp_42.pdf
Q 6 (b) y do we multiply the force with 2 to find the variation??

 

[ryanfarooqi]

Today the paper 21 was hard agree?
will they bring the threshold down?