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Yeah, did it the same way..Use the equation of motion s = ut + 0.5at^2
Now substitute the data into the equation
For XY
S= 40
t=12
u=??
a=??
equation 1 : 40 = 12u + 72a
For the X to Z
S= 80
t= 18
a=??
u=???
equation 2 : 80 = 18u + 162a
Why not I use the distance Y to Z is that it unitial velocity is different from that of X to Y
Now use simultaneus equation to get the answer..
I solved the question.... Actually i read the question incorrectly sorryI solved that even, link please so that I can copy my solution
Time is money.
Answer is D ?Can u also explain this question to me? Thought blocker ??? If u have time
No its CAnswer is D ?
Link dedoNo its C
U mean link of paper???Link dedo
It cannot b A becuz minimum momentum needed 2 stop da ball is 2mvCan u also explain this question to me? Thought blocker ??? If u have time
yupU mean link of paper???
How Pf = mv ?It cannot b A becuz minimum momentum needed 2 stop da ball is 2mv
If it wuz B den da ball wud stop at da wall becuz all momentum wud b removed.
D is wrong becuz momentum is conserved here
C is correct becuz inital p = 2mv , final p = mv , so da ball has lost momentum but it still rebounded
Use 0.5 * m * V^2
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